开源 企业版 高校版 私有云 模力方舟 AI 队友
代码拉取完成,页面将自动刷新
捐赠
捐赠前请先登录
扫描微信二维码支付
取消
支付完成
支付提示
将跳转至支付宝完成支付
确定
取消
1 Star 0 Fork 324

codingsills/Python

加入 Gitee
与超过 1400万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
已有帐号? 立即登录
文件
master
分支 (96)
master
pytest-run-parallel
delete-requirements.txt
pre-commit-ci-update-config
Python-3.14
uv-again
Sphinx-runs-on-ubuntu-24.04-arm
dependabot/github_actions/astral-sh/setup-uv-5
Shebang-python-for-Windows
gh-pages
Test-on-Python-3.13-beta
cclauss-patch-2
Keep-GitHub-Actions-up-to-date-with-Dependabot
Fewer-forward-propogations-to-speed-tests
cclauss-patch-1
Add-dataclasses-to-binary_search_tree.py
Simplify-is_bst.py
test-cov-gh-action
dhruv/remove
Remove-backslashes-from-is_palindrome.py
master
分支 (96)
master
pytest-run-parallel
delete-requirements.txt
pre-commit-ci-update-config
Python-3.14
uv-again
Sphinx-runs-on-ubuntu-24.04-arm
dependabot/github_actions/astral-sh/setup-uv-5
Shebang-python-for-Windows
gh-pages
Test-on-Python-3.13-beta
cclauss-patch-2
Keep-GitHub-Actions-up-to-date-with-Dependabot
Fewer-forward-propogations-to-speed-tests
cclauss-patch-1
Add-dataclasses-to-binary_search_tree.py
Simplify-is_bst.py
test-cov-gh-action
dhruv/remove
Remove-backslashes-from-is_palindrome.py
克隆/下载
克隆/下载
提示
下载代码请复制以下命令到终端执行
为确保你提交的代码身份被 Gitee 正确识别,请执行以下命令完成配置
初次使用 SSH 协议进行代码克隆、推送等操作时,需按下述提示完成 SSH 配置
1 生成 RSA 密钥
2 获取 RSA 公钥内容,并配置到 SSH公钥
在 Gitee 上使用 SVN,请访问 使用指南
使用 HTTPS 协议时,命令行会出现如下账号密码验证步骤。基于安全考虑,Gitee 建议 配置并使用私人令牌 替代登录密码进行克隆、推送等操作
Username for 'https://gitee.com': userName
Password for 'https://userName@gitee.com': # 私人令牌
master
分支 (96)
master
pytest-run-parallel
delete-requirements.txt
pre-commit-ci-update-config
Python-3.14
uv-again
Sphinx-runs-on-ubuntu-24.04-arm
dependabot/github_actions/astral-sh/setup-uv-5
Shebang-python-for-Windows
gh-pages
Test-on-Python-3.13-beta
cclauss-patch-2
Keep-GitHub-Actions-up-to-date-with-Dependabot
Fewer-forward-propogations-to-speed-tests
cclauss-patch-1
Add-dataclasses-to-binary_search_tree.py
Simplify-is_bst.py
test-cov-gh-action
dhruv/remove
Remove-backslashes-from-is_palindrome.py
simplex.py 11.56 KB
一键复制 编辑 原始数据 按行查看 历史
Christian Clauss 提交于 2024年10月01日 05:01 +08:00 . Upgrade to Python 3.13 (#11588)
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339
"""
Python implementation of the simplex algorithm for solving linear programs in
tabular form with
- `>=`, `<=`, and `=` constraints and
- each variable `x1, x2, ...>= 0`.
See https://gist.github.com/imengus/f9619a568f7da5bc74eaf20169a24d98 for how to
convert linear programs to simplex tableaus, and the steps taken in the simplex
algorithm.
Resources:
https://en.wikipedia.org/wiki/Simplex_algorithm
https://tinyurl.com/simplex4beginners
"""
from typing import Any
import numpy as np
class Tableau:
"""Operate on simplex tableaus
>>> Tableau(np.array([[-1,-1,0,0,1],[1,3,1,0,4],[3,1,0,1,4]]), 2, 2)
Traceback (most recent call last):
...
TypeError: Tableau must have type float64
>>> Tableau(np.array([[-1,-1,0,0,-1],[1,3,1,0,4],[3,1,0,1,4.]]), 2, 2)
Traceback (most recent call last):
...
ValueError: RHS must be > 0
>>> Tableau(np.array([[-1,-1,0,0,1],[1,3,1,0,4],[3,1,0,1,4.]]), -2, 2)
Traceback (most recent call last):
...
ValueError: number of (artificial) variables must be a natural number
"""
# Max iteration number to prevent cycling
maxiter = 100
def __init__(
self, tableau: np.ndarray, n_vars: int, n_artificial_vars: int
) -> None:
if tableau.dtype != "float64":
raise TypeError("Tableau must have type float64")
# Check if RHS is negative
if not (tableau[:, -1] >= 0).all():
raise ValueError("RHS must be > 0")
if n_vars < 2 or n_artificial_vars < 0:
raise ValueError(
"number of (artificial) variables must be a natural number"
)
self.tableau = tableau
self.n_rows, n_cols = tableau.shape
# Number of decision variables x1, x2, x3...
self.n_vars, self.n_artificial_vars = n_vars, n_artificial_vars
# 2 if there are >= or == constraints (nonstandard), 1 otherwise (std)
self.n_stages = (self.n_artificial_vars > 0) + 1
# Number of slack variables added to make inequalities into equalities
self.n_slack = n_cols - self.n_vars - self.n_artificial_vars - 1
# Objectives for each stage
self.objectives = ["max"]
# In two stage simplex, first minimise then maximise
if self.n_artificial_vars:
self.objectives.append("min")
self.col_titles = self.generate_col_titles()
# Index of current pivot row and column
self.row_idx = None
self.col_idx = None
# Does objective row only contain (non)-negative values?
self.stop_iter = False
def generate_col_titles(self) -> list[str]:
"""Generate column titles for tableau of specific dimensions
>>> Tableau(np.array([[-1,-1,0,0,1],[1,3,1,0,4],[3,1,0,1,4.]]),
... 2, 0).generate_col_titles()
['x1', 'x2', 's1', 's2', 'RHS']
>>> Tableau(np.array([[-1,-1,0,0,1],[1,3,1,0,4],[3,1,0,1,4.]]),
... 2, 2).generate_col_titles()
['x1', 'x2', 'RHS']
"""
args = (self.n_vars, self.n_slack)
# decision | slack
string_starts = ["x", "s"]
titles = []
for i in range(2):
for j in range(args[i]):
titles.append(string_starts[i] + str(j + 1))
titles.append("RHS")
return titles
def find_pivot(self) -> tuple[Any, Any]:
"""Finds the pivot row and column.
>>> tuple(int(x) for x in Tableau(np.array([[-2,1,0,0,0], [3,1,1,0,6],
... [1,2,0,1,7.]]), 2, 0).find_pivot())
(1, 0)
"""
objective = self.objectives[-1]
# Find entries of highest magnitude in objective rows
sign = (objective == "min") - (objective == "max")
col_idx = np.argmax(sign * self.tableau[0, :-1])
# Choice is only valid if below 0 for maximise, and above for minimise
if sign * self.tableau[0, col_idx] <= 0:
self.stop_iter = True
return 0, 0
# Pivot row is chosen as having the lowest quotient when elements of
# the pivot column divide the right-hand side
# Slice excluding the objective rows
s = slice(self.n_stages, self.n_rows)
# RHS
dividend = self.tableau[s, -1]
# Elements of pivot column within slice
divisor = self.tableau[s, col_idx]
# Array filled with nans
nans = np.full(self.n_rows - self.n_stages, np.nan)
# If element in pivot column is greater than zero, return
# quotient or nan otherwise
quotients = np.divide(dividend, divisor, out=nans, where=divisor > 0)
# Arg of minimum quotient excluding the nan values. n_stages is added
# to compensate for earlier exclusion of objective columns
row_idx = np.nanargmin(quotients) + self.n_stages
return row_idx, col_idx
def pivot(self, row_idx: int, col_idx: int) -> np.ndarray:
"""Pivots on value on the intersection of pivot row and column.
>>> Tableau(np.array([[-2,-3,0,0,0],[1,3,1,0,4],[3,1,0,1,4.]]),
... 2, 2).pivot(1, 0).tolist()
... # doctest: +NORMALIZE_WHITESPACE
[[0.0, 3.0, 2.0, 0.0, 8.0],
[1.0, 3.0, 1.0, 0.0, 4.0],
[0.0, -8.0, -3.0, 1.0, -8.0]]
"""
# Avoid changes to original tableau
piv_row = self.tableau[row_idx].copy()
piv_val = piv_row[col_idx]
# Entry becomes 1
piv_row *= 1 / piv_val
# Variable in pivot column becomes basic, ie the only non-zero entry
for idx, coeff in enumerate(self.tableau[:, col_idx]):
self.tableau[idx] += -coeff * piv_row
self.tableau[row_idx] = piv_row
return self.tableau
def change_stage(self) -> np.ndarray:
"""Exits first phase of the two-stage method by deleting artificial
rows and columns, or completes the algorithm if exiting the standard
case.
>>> Tableau(np.array([
... [3, 3, -1, -1, 0, 0, 4],
... [2, 1, 0, 0, 0, 0, 0.],
... [1, 2, -1, 0, 1, 0, 2],
... [2, 1, 0, -1, 0, 1, 2]
... ]), 2, 2).change_stage().tolist()
... # doctest: +NORMALIZE_WHITESPACE
[[2.0, 1.0, 0.0, 0.0, 0.0],
[1.0, 2.0, -1.0, 0.0, 2.0],
[2.0, 1.0, 0.0, -1.0, 2.0]]
"""
# Objective of original objective row remains
self.objectives.pop()
if not self.objectives:
return self.tableau
# Slice containing ids for artificial columns
s = slice(-self.n_artificial_vars - 1, -1)
# Delete the artificial variable columns
self.tableau = np.delete(self.tableau, s, axis=1)
# Delete the objective row of the first stage
self.tableau = np.delete(self.tableau, 0, axis=0)
self.n_stages = 1
self.n_rows -= 1
self.n_artificial_vars = 0
self.stop_iter = False
return self.tableau
def run_simplex(self) -> dict[Any, Any]:
"""Operate on tableau until objective function cannot be
improved further.
# Standard linear program:
Max: x1 + x2
ST: x1 + 3x2 <= 4
3x1 + x2 <= 4
>>> {key: float(value) for key, value in Tableau(np.array([[-1,-1,0,0,0],
... [1,3,1,0,4],[3,1,0,1,4.]]), 2, 0).run_simplex().items()}
{'P': 2.0, 'x1': 1.0, 'x2': 1.0}
# Standard linear program with 3 variables:
Max: 3x1 + x2 + 3x3
ST: 2x1 + x2 + x3 ≤ 2
x1 + 2x2 + 3x3 ≤ 5
2x1 + 2x2 + x3 ≤ 6
>>> {key: float(value) for key, value in Tableau(np.array([
... [-3,-1,-3,0,0,0,0],
... [2,1,1,1,0,0,2],
... [1,2,3,0,1,0,5],
... [2,2,1,0,0,1,6.]
... ]),3,0).run_simplex().items()} # doctest: +ELLIPSIS
{'P': 5.4, 'x1': 0.199..., 'x3': 1.6}
# Optimal tableau input:
>>> {key: float(value) for key, value in Tableau(np.array([
... [0, 0, 0.25, 0.25, 2],
... [0, 1, 0.375, -0.125, 1],
... [1, 0, -0.125, 0.375, 1]
... ]), 2, 0).run_simplex().items()}
{'P': 2.0, 'x1': 1.0, 'x2': 1.0}
# Non-standard: >= constraints
Max: 2x1 + 3x2 + x3
ST: x1 + x2 + x3 <= 40
2x1 + x2 - x3 >= 10
- x2 + x3 >= 10
>>> {key: float(value) for key, value in Tableau(np.array([
... [2, 0, 0, 0, -1, -1, 0, 0, 20],
... [-2, -3, -1, 0, 0, 0, 0, 0, 0],
... [1, 1, 1, 1, 0, 0, 0, 0, 40],
... [2, 1, -1, 0, -1, 0, 1, 0, 10],
... [0, -1, 1, 0, 0, -1, 0, 1, 10.]
... ]), 3, 2).run_simplex().items()}
{'P': 70.0, 'x1': 10.0, 'x2': 10.0, 'x3': 20.0}
# Non standard: minimisation and equalities
Min: x1 + x2
ST: 2x1 + x2 = 12
6x1 + 5x2 = 40
>>> {key: float(value) for key, value in Tableau(np.array([
... [8, 6, 0, 0, 52],
... [1, 1, 0, 0, 0],
... [2, 1, 1, 0, 12],
... [6, 5, 0, 1, 40.],
... ]), 2, 2).run_simplex().items()}
{'P': 7.0, 'x1': 5.0, 'x2': 2.0}
# Pivot on slack variables
Max: 8x1 + 6x2
ST: x1 + 3x2 <= 33
4x1 + 2x2 <= 48
2x1 + 4x2 <= 48
x1 + x2 >= 10
x1 >= 2
>>> {key: float(value) for key, value in Tableau(np.array([
... [2, 1, 0, 0, 0, -1, -1, 0, 0, 12.0],
... [-8, -6, 0, 0, 0, 0, 0, 0, 0, 0.0],
... [1, 3, 1, 0, 0, 0, 0, 0, 0, 33.0],
... [4, 2, 0, 1, 0, 0, 0, 0, 0, 60.0],
... [2, 4, 0, 0, 1, 0, 0, 0, 0, 48.0],
... [1, 1, 0, 0, 0, -1, 0, 1, 0, 10.0],
... [1, 0, 0, 0, 0, 0, -1, 0, 1, 2.0]
... ]), 2, 2).run_simplex().items()} # doctest: +ELLIPSIS
{'P': 132.0, 'x1': 12.000... 'x2': 5.999...}
"""
# Stop simplex algorithm from cycling.
for _ in range(Tableau.maxiter):
# Completion of each stage removes an objective. If both stages
# are complete, then no objectives are left
if not self.objectives:
# Find the values of each variable at optimal solution
return self.interpret_tableau()
row_idx, col_idx = self.find_pivot()
# If there are no more negative values in objective row
if self.stop_iter:
# Delete artificial variable columns and rows. Update attributes
self.tableau = self.change_stage()
else:
self.tableau = self.pivot(row_idx, col_idx)
return {}
def interpret_tableau(self) -> dict[str, float]:
"""Given the final tableau, add the corresponding values of the basic
decision variables to the `output_dict`
>>> {key: float(value) for key, value in Tableau(np.array([
... [0,0,0.875,0.375,5],
... [0,1,0.375,-0.125,1],
... [1,0,-0.125,0.375,1]
... ]),2, 0).interpret_tableau().items()}
{'P': 5.0, 'x1': 1.0, 'x2': 1.0}
"""
# P = RHS of final tableau
output_dict = {"P": abs(self.tableau[0, -1])}
for i in range(self.n_vars):
# Gives indices of nonzero entries in the ith column
nonzero = np.nonzero(self.tableau[:, i])
n_nonzero = len(nonzero[0])
# First entry in the nonzero indices
nonzero_rowidx = nonzero[0][0]
nonzero_val = self.tableau[nonzero_rowidx, i]
# If there is only one nonzero value in column, which is one
if n_nonzero == 1 and nonzero_val == 1:
rhs_val = self.tableau[nonzero_rowidx, -1]
output_dict[self.col_titles[i]] = rhs_val
return output_dict
if __name__ == "__main__":
import doctest
doctest.testmod()
Loading...
举报
举报成功
我们将于2个工作日内通过站内信反馈结果给你!
请认真填写举报原因,尽可能描述详细。
请选择举报类型
取消
发送
误判申诉

此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。

如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。

取消
提交

简介

Python 算法集
暂无标签
MIT
使用 MIT 开源许可协议
取消

发行版

暂无发行版

贡献者

全部

近期动态

不能加载更多了
编辑仓库简介
简介内容
主页
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
Python
1
https://gitee.com/codingsills/Python.git
git@gitee.com:codingsills/Python.git
codingsills
Python
Python
master
点此查找更多帮助

搜索帮助

评论
仓库举报
回到顶部
登录提示
该操作需登录 Gitee 帐号,请先登录后再操作。
立即登录
没有帐号,去注册

AltStyle によって変換されたページ (->オリジナル) /