Method Invocation: Argument Evaluation Order

Wed Oct 16 01:19:00 GMT 2002

Hi,
 According to the JLS (section 15.12.4.2, "Evaluate Arguments")
while evaluating the arguments passed to a method invocation:
http://java.sun.com/docs/books/jls/second_edition/html/expressions.doc.html#45449
"The argument expressions are evaluated in order, from left to right..."
Therefore the following program should output (as it indeed
does with the Sun JDK 1.3.1):
a = 0
b = 1
But instead, with GCJ 3.2 on Solaris, it outputs:
a = 1
b = 1
The program in question is:
-------------------------- 8< ----------------------------
public class PreIncr
{
 private int i = 0;
 public static void main( String[] args)
 {
 new PreIncr( ).doIt( );
 }
 private void doIt( )
 {
 this.printAB( i, ++i);
 }
 private void printAB( int a, int b)
 {
 System.out.println( "a = " + a);
 System.out.println( "b = " + b);
 }
}
-------------------------- 8< ----------------------------
Isn't this a bug? Or am I missing something here?
Ranjit.
-- 
Ranjit Mathew Email: rmathew AT hotmail DOT com
Bangalore, INDIA. Web: http://ranjitmathew.tripod.com/