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How to make IRA not to move an instruction
- From: "H.J. Lu" <hjl dot tools at gmail dot com>
- To: Vladimir Makarov <vmakarov at redhat dot com>, GCC Development <gcc at gcc dot gnu dot org>
- Date: 2010年5月28日 09:38:30 -0700
- Subject: How to make IRA not to move an instruction
Hi,
I want to generate vzeroupper when I know upper 128bits aren't used. I
can't find
a way to mark an pattern which zeros upper 128bits. So I added
;; Clear the upper 128bits of AVX registers, equivalent to a NOP.
;; This should be used only when the upper 128bits are unused.
(define_insn "avx_vzeroupper_nop"
[(unspec_volatile [(const_int 0)] UNSPECV_VZEROUPPER)]
"TARGET_AVX"
"vzeroupper"
[(set_attr "type" "sse")
(set_attr "modrm" "0")
(set_attr "memory" "none")
(set_attr "prefix" "vex")
(set_attr "mode" "OI")])
For this simple code,
---
typedef float __m256 __attribute__ ((__vector_size__ (32),
__may_alias__));
extern __m256 x, z;
extern void bar2 (void);
int
foo (__m256 y)
{
bar2 ();
z = y;
return 0;
}
---
before IRA,
(insn 2 4 3 2 x.i:9 (set (reg/v:V8SF 59 [ y ])
(reg:V8SF 21 xmm0 [ y ])) 1036 {*avx_movv8sf_internal}
(expr_list:REG_DEAD (reg:V8SF 21 xmm0 [ y ])
(nil)))
(note 3 2 6 2 NOTE_INSN_FUNCTION_BEG)
(insn 6 3 7 2 x.i:10 (unspec_volatile [
(const_int 0 [0])
] 17) 1960 {avx_vzeroupper_nop} (nil))
(call_insn 7 6 8 2 x.i:10 (call (mem:QI (symbol_ref:DI ("bar2") [flags
0x41] <function_decl 0x7ffa930ecd00 bar2>) [0 S1 A8])
(const_int 0 [0])) 599 {*call_0} (nil)
(nil))
after IRA,
(insn 6 3 20 2 x.i:10 (unspec_volatile [
(const_int 0 [0])
] 17) 1960 {avx_vzeroupper_nop} (nil))
(insn 20 6 7 2 x.i:10 (set (mem/c:V8SF (reg/f:DI 7 sp) [3 S32 A256])
(reg:V8SF 21 xmm0)) 1036 {*avx_movv8sf_internal} (nil))
(call_insn 7 20 21 2 x.i:10 (call (mem:QI (symbol_ref:DI ("bar2")
[flags 0x41] <function_decl 0x7ffa930ecd00 bar2>) [0 S1 A8])
(const_int 0 [0])) 599 {*call_0} (nil)
(nil))
Since vzeroupper will change xmm0/ymm0, the value saved on stack is wrong.
Is that a way to tell IRA not to move an instruction?
Thanks.
--
H.J.