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Summary

DescriptionBayes theorem visualisation.svg
English: A geometric visualisation of Bayes' theorem by CMG Lee. The thumbnails denote the number of each corresponding condition and case, the probability being the fraction of each thumbnail that is shaded. Similar reasoning can be used to show that P(Ā|B) = ⁠P(B|Ā) P(Ā)/P(B)⁠ etc.
Source Own work
Author Cmglee
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Bayes theorem assassin.svg
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Date/TimeThumbnailDimensionsUserComment
current12:28, 16 October 2022 Thumbnail for version as of 12:28, 16 October 2022 512 ×ばつ 768 (10 KB)Cmglee http://commons.wikimedia.org/w/index.php?title=File_talk:Bayes_theorem_assassin.svg&diff=0&oldid=693178688 // Editing SVG source code using c:User:Rillke/SVGedit.js
12:33, 15 February 2022 Thumbnail for version as of 12:33, 15 February 2022 512 ×ばつ 768 (10 KB)Cmglee Reorder equations to match File:Bayes_theorem_assassin.svg
19:00, 13 February 2022 Thumbnail for version as of 19:00, 13 February 2022 512 ×ばつ 768 (10 KB)Cmglee Reverted to version as of 02:58, 30 September 2019 (UTC): uploaded to wrong file
18:07, 13 February 2022 Thumbnail for version as of 18:07, 13 February 2022 512 ×ばつ 768 (10 KB)Cmglee Align text
02:58, 30 September 2019 Thumbnail for version as of 02:58, 30 September 2019 512 ×ばつ 768 (10 KB)Cmglee Avoid black face.
02:44, 30 September 2019 Thumbnail for version as of 02:44, 30 September 2019 512 ×ばつ 768 (10 KB)Cmglee Add backronyms.
13:52, 24 March 2018 Thumbnail for version as of 13:52, 24 March 2018 512 ×ばつ 768 (10 KB)Cmglee Add icons with Accessory and Beard.
13:26, 14 March 2018 Thumbnail for version as of 13:26, 14 March 2018 512 ×ばつ 853 (8 KB)Cmglee Fix misaligned denominator.
13:19, 14 March 2018 Thumbnail for version as of 13:19, 14 March 2018 512 ×ばつ 853 (8 KB)Cmglee Use numbers and colours.
17:46, 22 March 2015 Thumbnail for version as of 17:46, 22 March 2015 512 ×ばつ 384 (8 KB)Olexa Riznyk Ukrainian localization added
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Short titleBayes theorem visualisation
Image titleA geometric visualisation of Bayes' theorem by CMG Lee. The thumbnails denote the number of each corresponding condition and case, the probability being the fraction of each thumbnail that is shaded. Similar reasoning can be used to show that P(Ā|B) = P(B|Ā) P(Ā) / P(B) etc.
Width100%
Height100%

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