2016 Launceston Tennis International – Men's doubles
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| Men's doubles | |||||||
|---|---|---|---|---|---|---|---|
| 2016 Launceston Tennis International | |||||||
| Final | |||||||
| Champion | Australia Luke Saville Australia Jordan Thompson | ||||||
| Runner-up | Australia Dayne Kelly Australia Matt Reid | ||||||
| Score | 6–1 , 4–6 , [13–11] | ||||||
| Events | |||||||
| |||||||
2016 tennis event results
Main article: 2016 Launceston Tennis International
Radu Albot and Mitchell Krueger are the defending champions, but chose not to defend their title .
Luke Saville and Jordan Thompson won the title, defeating Dayne Kelly and Matt Reid in the final 6–1, 4–6, [13–11] .
Seeds
[edit ]- Kazakhstan Andrey Golubev / India Saketh Myneni (semifinals)
- Australia Alex Bolt / Australia Andrew Whittington (quarterfinals)
- United Kingdom Brydan Klein / Japan Toshihide Matsui (quarterfinals)
- Australia Steven de Waard / Australia Marc Polmans (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round
Quarterfinals
Semifinals
Final
WC
Australia J Delaney
Australia M Purcell 3 5 United States A Sarkissian
New Zealand F Tearney 66 1
Australia M Purcell 3 5 United States A Sarkissian
New Zealand F Tearney 66 1
WC
Australia T Fancutt
Australia C Puttergill 2 3 2 Australia A Bolt
Australia A Whittington 3 6 [7]
Australia C Puttergill 2 3 2 Australia A Bolt
Australia A Whittington 3 6 [7]