2022年07月11日 21:15

Tae Joo

edited: 2022年07月11日 21:16

print(int('10000',9))

0~9999(9진법)에 수가 몇 개 있느냐 즉 답은 10000(9진법)인 문제입니다.

print(len([ x for x in range(10000) if '8' not in str(x) ]))

결과: 6561

파이썬 3.8.5

alist = []
cc = 0
for ii in range(10000):
 c = 0
 for i in str(ii):
 if i == '8':
 c = 1
 if c == 0:
 cc += 1
print(cc)

count = 0
for i in range(0, 10000):
 a = list(str(i))
 if "8" not in a:
 count += 1
print(count)

파이썬으로 풀이해보았습니다.

len([x for x in range(10000) if "8" not in str(x)])

count=0
for i in range(10000):
 if "8" in str(i):
 count+=1
print(10000-count)

a = []
for i in range(10000):
 if "8" not in str(i):
 a.append(i)
print(len(a))

def res(s_num):
 re = 0
 for i in range(s_num+1):
 if '8' not in str(i):
 re += 1
 return re
print(res(10000))

count = 0
for i in range(0,10000) :
 f = str(i)
 if '8' not in f : count = count + 1 
print(count)

cnt=0
for i in range(10000):
 if(not '8' in str(i)):
 cnt += 1
print(cnt)