2015年09月15日 22:40

Straß Böhm Jäger

edited: 2015年09月15日 22:41

c# 입니다.

 private void Form1_Load(object sender, EventArgs e)
 {
 String inputs = "0123456789 01234 01234567890 6789012345 012322456789";
 String[] Split_input = inputs.Split(' ');
 foreach (String s in Split_input)
 {
 if (Check_NUM(s))
 Console.Write("true ");
 else
 Console.Write("false ");
 }
 }
 private bool Check_NUM(String number)
 {
 List<Char> List_input = new List<Char>();
 char[] data = number.ToCharArray();
 foreach (Char d in data)
 {
 if (List_input.Contains(d))
 return false;
 List_input.Add(d);
 }
 if (List_input.Count == 10)
 return true;
 return false;
 }

공백을 나눈 후 String을 Char 배열로 쪼개서 넣은다음 list클래스의 contain으로 값이 들어있는지 비교를 해보았습니다.

a = list(input("0~9까지 숫자를 한번씩 입력하시오 :"))

print ("True" if '0123456789' == "".join(sorted(a)) else "False")

(defn ^int to-int [^Character c]
 (Character/getNumericValue c))
(let [FULLNUMBER 2r1111111111]
 (defn ^boolean is-fullnumbers?
 [^String numbers]
 (loop [[x & xs] (map to-int numbers)
 acc 2r0]
 (let [is-fulled (= acc FULLNUMBER)]
 (cond (nil? x) is-fulled
 (and is-fulled x xs) false
 :else
 (let [shifted (bit-shift-left 1 x)]
 (if-not (zero? (bit-and acc shifted))
 false
 (recur xs (bit-or acc shifted)))))))))
(time (map is-fullnumbers? ["0123456789" "01234" "01234567890" "6789012345" "012322456789"]))
;=> (true false false true false)

Swift로 간단하게 풀었습니다.

let answer = "0123456789".utf8.reduce(0) { 0ドル + Int(1ドル) }
let input = ["0123456789", "01234", "01234567890", "6789012345", "012322456789"];
let output = input.map { 0ドル.utf8.reduce(0) { 0ドル + Int(1ドル) } == answer }
print(output) // [true, false, false, true, false]

VB.NET

 Dim test_case() As Integer = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
 Dim result As Boolean = Enumerable.Range(0, 10).SequenceEqual(test_case)
 Console.WriteLine(result)

insertion = input()

palette = [] for i in range(0, len(insertion)): palette.append(int(insertion[i]))

contrast = list(set(sorted(palette)))

if palette == contrast: print("true") else: print("false")

!/usr/bin/python

box=range(0,10) values=raw_input("> ") for i in values: box.remove(int(i)) if box: print 'false!' else: print 'true!'

include

include

int main() { int i; int a[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0}; char c[256]; fgets(c, sizeof(c), stdin); c[strlen(c)-1] = '0円';

if (strlen(c) != 10) {
 printf("False\n");
 return 0;
}
for (i = 0; i < 10; i++) {
 a[(int)(c[i])-48]++;
}
for (i = 0; i < 10; i++) {
 if (a[i] != 1) {
 printf("False\n");
 return 0;
 }
}
printf("True\n");
return 0;

}

Duplicate number.py

def check(s):

result = []
for num in s:
 result.append(num)
result = list(set(result))
if len(s) != 10 or len(result) != 10 :
 return False
return True

print(check("0123456789"))

//이게 레벨이 1이...????

include

include

using namespace std;

int main() { int innum; string firstin; int count; bool flag; int num[10] = { 0 };

cout << "숫자 입력 >> ";
cin >> firstin;
int coutn = 0;
innum = stoi(firstin);
count = 0;
flag = 0;
for (int ws = innum;;)
{
 coutn++;
 if(ws != 0) num[ws % 10]++;
 if (ws < 10) break;
 ws /= 10;
}
for (int i = 0; i < coutn-1; i++)
{
 if (firstin[i] == '0') num[0]++;
}
for (int i = 0; i < 10; i++)
{
 cout << "num[" << i << "] = " << num[i] << endl;
 if (num[i] != 1) flag = 1;
}
if (flag) cout << "false" << endl;
else cout << "ture" << endl;

}