Back in my calculator post calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel - 1); // use "- 1" because value increments just before ending loop
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel - 1); // use "- 1" because value increments just before ending loop
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel - 1); // use "- 1" because value increments just before ending loop
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel == 0- ?1); decimalLevel :// decimalLeveluse "- 1);1" because value increments just before ending loop
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel == 0 ? decimalLevel : decimalLevel - 1);
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel - 1); // use "- 1" because value increments just before ending loop
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel - 1); // use "- 1"== because0 value? incrementsdecimalLevel just: beforedecimalLevel ending- loop1);
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel - 1); // use "- 1" because value increments just before ending loop
}
Please analyze my code as thoroughly as the compiler does.
Back in my calculator post, janos suggested I either find a better way to read a double from a StreamReader or else go the whole way and build a double from scratch. I looked through a few streams, but the only one I found that supported reading a double was the BinaryReader. This, unfortunately, reads exactly 8 bytes, and the data is stored as a char (or rather, as an int representation of a char), so I could enter the equation "5+5", and it would crash when it read the "+". If you know of a better solution, I would prefer using it.
private double GetNextNumber(StreamReader dataStream)
{
double value = 0;
int decimalLevel = 0;
while (true)
{
if (!"0123456789.".Contains((char)dataStream.Peek()))
{
break;
}
char token = (char)dataStream.Read();
if (token == '.')
{
if (decimalLevel == 0)
{
++decimalLevel;
continue;
}
throw new InvalidDataException("Invalid number format.");
}
int digit = int.Parse(token.ToString());
value = value * 10 + digit;
if (decimalLevel != 0)
{
++decimalLevel;
}
}
return value / Math.Pow(10, decimalLevel == 0 ? decimalLevel : decimalLevel - 1);
}
Please analyze my code as thoroughly as the compiler does.