Question Description:

Given a number n, return True if n is in the range 1..10, inclusive. Unless outsideMode is True, in which case return True if the number is less or equal to 1, or greater or equal to 10.

in1to10(5, False) → **True**
in1to10(11, False) → **False**
in1to10(11, True) → **True**

The link to the problem is here.

Below is my first attempt. Please feel free to review it based on best practices, style and any other efficient solution.

def in1to10(n, outside_mode):
 if(n>1 and n<10):
 return not outside_mode
 else:
 return outside_mode or n is 10 or n is 1

Question Description:

Given a number n, return True if n is in the range 1..10, inclusive. Unless outsideMode is True, in which case return True if the number is less or equal to 1, or greater or equal to 10.

in1to10(5, False) → **True**
in1to10(11, False) → **False**
in1to10(11, True) → **True**

The link to the problem is here.

Below is my first attempt. Please feel free to review it based on best practices, style and any other efficient solution.

def in1to10(n, outside_mode):
 if(n>1 and n<10):
 return not outside_mode
 else:
 return outside_mode or n is 10 or n is 1

I am starting out on Python below is the question Description:

Given a number n, return True if n is in the range 1..10, inclusive. Unless "outsideMode" is True, in which case return True if the number is less or equal to 1, or greater or equal to 10.

in1to10(5, False) → **True**
in1to10(11, False) → **False**
in1to10(11, True) → **True**

The link to the problem is here

Below is my first attempt, Please feel free to review it based on best practices, style and any other efficient solution.

def in1to10(n, outside_mode):
 if(n>1 and n<10):
 return not outside_mode
 else:
 return outside_mode or n is 10 or n is 1

Question Description:

Given a number n, return True if n is in the range 1..10, inclusive. Unless outsideMode is True, in which case return True if the number is less or equal to 1, or greater or equal to 10.

in1to10(5, False) → **True**
in1to10(11, False) → **False**
in1to10(11, True) → **True**

The link to the problem is here .

Below is my first attempt. Please feel free to review it based on best practices, style and any other efficient solution.

def in1to10(n, outside_mode):
 if(n>1 and n<10):
 return not outside_mode
 else:
 return outside_mode or n is 10 or n is 1