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deleted 3 characters in body; edited tags; edited title

edited Aug 30, 2015 at 20:17

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JSON fetcher for Eclipse plugin — Is this exemplary code for exception handling?

This is a client module of an Eclipse plugin. I am planning to use this code as a "good exception handling" code example in one of my papers. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
BufferedReader breader=null;
try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
}catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
}catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
}
catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
}
finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
}

JSON fetcher for Eclipse plugin — Is this exemplary code for exception handling?

I am planning to use this code as a "good exception handling" code example in one of my papers. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
BufferedReader breader=null;
try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
}catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
}catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
}
catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
}
finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
}

JSON fetcher for Eclipse plugin

This is a client module of an Eclipse plugin. I am planning to use this code as a "good exception handling" code example in one of my papers. How does it look?

HttpURLConnection httpconn=null;
BufferedReader breader=null;
try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
}catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
}catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
}
catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
}
finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
}

Reduced excessive indentation. Edited title.

Source Link

edited Jun 24, 2014 at 14:09

200_success

edited Jun 24, 2014 at 14:09

200_success

145.5k
22
190
478

Exception handling - JSON fetcher for Eclipse plugin — Is this exemplary code examplefor exception handling?

I am planning to use this code as a 'good"good exception handling'handling" code example in one of my papers. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
BufferedReader breader=null;
try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
}catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
}catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
}
catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
}
finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
}

Exception handling - code example

I am planning to use this code as a 'good exception handling' code example in one of my papers. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
BufferedReader breader=null;
try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
}catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
}catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
}
catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
}
finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
}

JSON fetcher for Eclipse plugin — Is this exemplary code for exception handling?

I am planning to use this code as a "good exception handling" code example in one of my papers. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
BufferedReader breader=null;
try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
}catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
}catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
}
catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
}
finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
}

java exception-handling http eclipse

typos and add java tag - make title reflect what the code does, not what is requested with the review.

Source Link

edited Jun 24, 2014 at 11:21

rolfl

edited Jun 24, 2014 at 11:21

rolfl

98.1k
17
219
419

How good is this exception Exception handling - code example?

I am planning to use this onecode as a good'good exception handlinghandling' code example in one of my paperpapers. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
 BufferedReader breader=null;
 try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
 }catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
 }catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
 }
 catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
 }
 finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
 }

How good is this exception handling code example?

I am planning to use this one as a good exception handling code example in one of my paper. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
 BufferedReader breader=null;
 try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
 }catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
 }catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
 }
 catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
 }
 finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
 }

Exception handling - code example

I am planning to use this code as a 'good exception handling' code example in one of my papers. It is for a client module of an Eclipse plugin. How does it look?

HttpURLConnection httpconn=null;
 BufferedReader breader=null;
 try{ 
 URL url=new URL(this.web_service_url);
 httpconn=(HttpURLConnection)url.openConnection();
 httpconn.setRequestMethod("GET");
 System.out.println(httpconn.getResponseMessage());
 if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK)
 {
 breader=new BufferedReader(new InputStreamReader(httpconn.getInputStream()));
 String line=null;
 while((line=breader.readLine())!=null)
 {
 jsonResponse+=line;
 }
 //System.out.println(jsonResponse);
 //display_json_results(jsonResponse);
 }
 }catch(MalformedURLException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid URL", e.getMessage());
 }catch(ProtocolException e){
 MessageDialog.openError(Display.getDefault().getShells()[0], "Invalid Protocol", e.getMessage());
 }
 catch(IOException e2){
 Log.info("Failed to access the data"+e2.getMessage());
 }
 finally{
 try{
 breader.close();}catch(IOException e){
 Log.info("Failed to release resources"+e.getMessage());
 }
 
 }

java exception-handling eclipse

Source Link

asked Jun 24, 2014 at 9:26

Masud Rahman

asked Jun 24, 2014 at 9:26

Masud Rahman

lang-java