I'm using code adapted from this Stack Overflow question to calculate all possible combinations from an array, which may contains strings.

For example:

[ "x", "y", "z" ] => "x y z"
[ [ "a", "b"] , "c", "d" ] => [ "a c d", "b c d" ]
[ [ "a", "b"] , ["c" "d"], "e"] => [ "a c e", "b c e", "a d e", "b d e" ]

However as the items could be strings or array I need to check for all possible combinations of array/string pairs when building the results.

This has ended in rather messy code, and I'd appreciate any hints on how to tidy it up. I've attempted to refactor it, but I guess I'm tired and missing something!

function allPossibleCases(arr) {
 if (arr.length === 0) {
 return [];
 } 
 else if (arr.length === 1){
 return arr[0];
 }
 else {
 var result = [];
 var allCasesOfRest = allPossibleCases(arr.slice(1)); // recur with the rest of array
 if(typeof allCasesOfRest === 'string') {
 if(typeof arr[0] === 'string') {
 result.push(arr[0] + " " + allCasesOfRest);
 } else { 
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest);
 }
 }
 }
 
 else {
 for (var c in allCasesOfRest) {
 if(typeof arr[0] === 'string') { 
 result.push(arr[0] + " " + allCasesOfRest[c]);
 } else {
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest[c]);
 }
 }
 }
 }
 return result;
 }
}

I'm using code adapted from this Stack Overflow question to calculate all possible combinations from an array, which may contains strings.

For example:

[ "x", "y", "z" ] => "x y z"
[ [ "a", "b"] , "c", "d" ] => [ "a c d", "b c d" ]
[ [ "a", "b"] , ["c" "d"], "e"] => [ "a c e", "b c e", "a d e", "b d e" ]

However as the items could be strings or array I need to check for all possible combinations of array/string pairs when building the results.

This has ended in rather messy code, and I'd appreciate any hints on how to tidy it up. I've attempted to refactor it, but I guess I'm tired and missing something!

function allPossibleCases(arr) {
 if (arr.length === 0) {
 return [];
 } 
 else if (arr.length === 1){
 return arr[0];
 }
 else {
 var result = [];
 var allCasesOfRest = allPossibleCases(arr.slice(1)); // recur with the rest of array
 if(typeof allCasesOfRest === 'string') {
 if(typeof arr[0] === 'string') {
 result.push(arr[0] + " " + allCasesOfRest);
 } else { 
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest);
 }
 }
 }
 
 else {
 for (var c in allCasesOfRest) {
 if(typeof arr[0] === 'string') { 
 result.push(arr[0] + " " + allCasesOfRest[c]);
 } else {
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest[c]);
 }
 }
 }
 }
 return result;
 }
}

I'm using code adapted from http://stackoverflow.com/questions/4331092/finding-all-combinations-of-javascript-array-values to calculate all possible combinations from an array, which may contains strings

For example

[ "x", "y", "z" ] => "x y z"
[ [ "a", "b"] , "c", "d" ] => [ "a c d", "b c d" ]
[ [ "a", "b"] , ["c" "d"], "e"] => [ "a c e", "b c e", "a d e", "b d e" ]

function allPossibleCases(arr) {
 if (arr.length === 0) {
 return [];
 } 
 else if (arr.length === 1){
 return arr[0];
 }
 else {
 var result = [];
 var allCasesOfRest = allPossibleCases(arr.slice(1)); // recur with the rest of array
 if(typeof allCasesOfRest === 'string') {
 if(typeof arr[0] === 'string') {
 result.push(arr[0] + " " + allCasesOfRest);
 } else { 
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest);
 }
 }
 }
 
 else {
 for (var c in allCasesOfRest) {
 if(typeof arr[0] === 'string') { 
 result.push(arr[0] + " " + allCasesOfRest[c]);
 } else {
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest[c]);
 }
 }
 }
 }
 return result;
 }
}

I'm using code adapted from this Stack Overflow question to calculate all possible combinations from an array, which may contains strings.

For example:

[ "x", "y", "z" ] => "x y z"
[ [ "a", "b"] , "c", "d" ] => [ "a c d", "b c d" ]
[ [ "a", "b"] , ["c" "d"], "e"] => [ "a c e", "b c e", "a d e", "b d e" ]

function allPossibleCases(arr) {
 if (arr.length === 0) {
 return [];
 } 
 else if (arr.length === 1){
 return arr[0];
 }
 else {
 var result = [];
 var allCasesOfRest = allPossibleCases(arr.slice(1)); // recur with the rest of array
 if(typeof allCasesOfRest === 'string') {
 if(typeof arr[0] === 'string') {
 result.push(arr[0] + " " + allCasesOfRest);
 } else { 
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest);
 }
 }
 }
 
 else {
 for (var c in allCasesOfRest) {
 if(typeof arr[0] === 'string') { 
 result.push(arr[0] + " " + allCasesOfRest[c]);
 } else {
 for (var i = 0; i < arr[0].length; i++) {
 result.push(arr[0][i] + " " + allCasesOfRest[c]);
 }
 }
 }
 }
 return result;
 }
}