You're misunderstanding how the static static keyword works.
The first time it is encountered for a specific variable in the method it defines the $inst variable as null, then checks to see if it is null (it is :p) and then sets it to a new object of that class.
The second time, the static definition isn't used because the static variable has already been defined. It then checks to see if it is null, it isn't, it has already been set to a new object of the class, so it skips the if and returns the object.
You're misunderstanding how the static keyword works.
The first time it is encountered for a specific variable in the method it defines the $inst variable as null, then checks to see if it is null (it is :p) and then sets it to a new object of that class.
The second time, the static definition isn't used because the static variable has already been defined. It then checks to see if it is null, it isn't, it has already been set to a new object of the class, so it skips the if and returns the object.
You're misunderstanding how the static keyword works.
The first time it is encountered for a specific variable in the method it defines the $inst variable as null, then checks to see if it is null (it is :p) and then sets it to a new object of that class.
The second time, the static definition isn't used because the static variable has already been defined. It then checks to see if it is null, it isn't, it has already been set to a new object of the class, so it skips the if and returns the object.
You're misunderstanding how the static keyword works.
The first time it is encountered for a specific variable in the method it defines the $inst variable as null, then checks to see if it is null (it is :p) and then sets it to a new object of that class.
The second time, the static definition isn't used because the static variable has already been defined. It then checks to see if it is null, it isn't, it has already been set to a new object of the class, so it skips the if and returns the object.