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Bug ? cannot resolve symbol 'isatty': Procedure not found #35

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opened 2018年04月17日 15:32:08 +02:00 by droslean · 7 comments
droslean commented 2018年04月17日 15:32:08 +02:00 (Migrated from github.com)
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cannot resolve symbol 'isatty': Procedure not found

cannot resolve symbol 'isatty': Procedure not found
droslean commented 2018年04月17日 15:32:19 +02:00 (Migrated from github.com)
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debugger.lua:466

debugger.lua:466
slembcke commented 2018年04月17日 16:53:21 +02:00 (Migrated from github.com)
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What interpreter/version are you using?

What interpreter/version are you using?
droslean commented 2018年04月17日 17:03:01 +02:00 (Migrated from github.com)
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Lua 5.3.4

Lua 5.3.4
aleclarson commented 2018年04月19日 16:52:16 +02:00 (Migrated from github.com)
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Possibly same bug as #12

Thanks for the report!

Possibly same bug as #12 Thanks for the report!
ghost commented 2019年02月23日 02:26:47 +01:00 (Migrated from github.com)
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There is no isatty function on Windows. You should use the one provided by the Windows.h header file which is _isatty.

There is no `isatty` function on Windows. You should use the one provided by the `Windows.h` header file which is `_isatty`.
aleclarson commented 2019年02月23日 02:27:51 +01:00 (Migrated from github.com)
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@xorz57 Pull requests greatly appreciated! No one is actively maintaining this.

@xorz57 Pull requests greatly appreciated! No one is actively maintaining this.
ghost commented 2019年02月23日 02:33:12 +01:00 (Migrated from github.com)
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I just saw this issue while searching the same warning on google. I don't know lua language to be able to write something decent but maybe I will give it a try. Also if you had some automated building mechanism for this project, that would make me feel more comfortable because I would know if I broke something.

I just saw this issue while searching the same warning on google. I don't know lua language to be able to write something decent but maybe I will give it a try. Also if you had some automated building mechanism for this project, that would make me feel more comfortable because I would know if I broke something.
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