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As I understood the long object allocation it is implemented as
"PyObject_MALLOC(sizeof(PyVarObject) + size*sizeof(digit))" to avoid
this allocation of extra 2 bytes. So from my understanding, the number 0
allocates memory for the reference count, type, and ob_size, whereas any
other number allocates this plus additional memory required by the
number of digits.
Looking at bool objects in Py3k, arn't they fixed-sized memory-wise,
always allocating the the padded size of _longobject?
> In any case, I also think this doesn't matter much either way. 
Why do you think so?