Message273133
| Author |
r.david.murray |
| Recipients |
ezio.melotti, martin.panter, mrabarnett, r.david.murray |
| Date |
2016年08月19日.15:03:59 |
| SpamBayes Score |
-1.0 |
| Marked as misclassified |
Yes |
| Message-id |
<1471619039.65.0.0624282048448.issue27800@psf.upfronthosting.co.za> |
| In-reply-to |
| Content |
It seems perfectly logical and consistent to me. {4} is a repeat count, as is *. You get the same error if you do 'a?*', and the same bypass if you do '(a?)*' (though I haven't tested if that does anything useful :). You don't need the ?:, as far as I can tell, you just need to have the * modifying a group, making the group the "preceding regular expression". |
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History
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| Date |
User |
Action |
Args |
| 2016年08月19日 15:03:59 | r.david.murray | set | recipients:
+ r.david.murray, ezio.melotti, mrabarnett, martin.panter |
| 2016年08月19日 15:03:59 | r.david.murray | set | messageid: <1471619039.65.0.0624282048448.issue27800@psf.upfronthosting.co.za> |
| 2016年08月19日 15:03:59 | r.david.murray | link | issue27800 messages |
| 2016年08月19日 15:03:59 | r.david.murray | create |
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