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"""
Will the following code compile OK? What will it compile to?
 if 1:
 42
"""
compile OK: what do you mean? This code doesn't make any sense to me :-)
Currently text strings statements are ignored:
---
>>> def f():
... if 1:
... "abc"
... 
>>> import dis
>>> dis.dis(f)
 3 0 LOAD_CONST 0 (None)
 3 RETURN_VALUE
---
But byte strings emit a LOAD_CONST+POP_TOP:
---
>>> def g():
... if 1:
... b'bytes'
... 
>>> dis.dis(g)
 3 0 LOAD_CONST 1 (b'bytes')
 3 POP_TOP
 4 LOAD_CONST 0 (None)
 7 RETURN_VALUE
---
With my patch, all constants statements will be ignored. Example with my patch:
---
>>> def h():
... if 1:
... b'bytes'
... 
>>> import dis; dis.dis(h)
 3 0 LOAD_CONST 0 (None)
 3 RETURN_VALUE
---