Message258045
| Author |
gvanrossum |
| Recipients |
benhoyt, gvanrossum, martin.panter, serhiy.storchaka, vstinner |
| Date |
2016年01月12日.00:40:11 |
| SpamBayes Score |
-1.0 |
| Marked as misclassified |
Yes |
| Message-id |
<1452559211.7.0.783884488227.issue25994@psf.upfronthosting.co.za> |
| In-reply-to |
| Content |
It was a bit more subtle. I think like this:
def f():
with some_lock:
yield 0
yield 1
def g():
with another_lock:
it = f()
for i in it:
raise
We determined that another_lock was freed *before* some_lock. This is because the local variable 'it' keeps the generator object returned by f() alive until after the with-block in g() has released another_lock.
I think this does not strictly require f to be a generator -- it's any kind of closable resource that only gets closed by its destructor.
The solution is to add a try/finally that calls it.close() before leaving the with-block in g().
Hope this helps. |
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