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This is valid:
 ℘· = 1
 print(℘·)
 #>>> 1
But this gives an error token:
 from io import BytesIO
 from tokenize import tokenize
 stream = BytesIO("℘·".encode("utf-8"))
 print(*tokenize(stream.read), sep="\n")
 #>>> TokenInfo(type=56 (ENCODING), string='utf-8', start=(0, 0), end=(0, 0), line='')
 #>>> TokenInfo(type=53 (ERRORTOKEN), string='℘', start=(1, 0), end=(1, 1), line='℘·')
 #>>> TokenInfo(type=53 (ERRORTOKEN), string='·', start=(1, 1), end=(1, 2), line='℘·')
 #>>> TokenInfo(type=0 (ENDMARKER), string='', start=(2, 0), end=(2, 0), line='')
This is a continuation of http://bugs.python.org/issue9712. I'm not able to reopen the issue, so I thought I should report it anew.
It is tokenize that is wrong - Other_ID_Start and Other_ID_Continue are documented to be valid:
https://docs.python.org/3.5/reference/lexical_analysis.html#identifiers