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| Author | mrabarnett |
|---|---|
| Recipients | docs@python, ezio.melotti, georg.brandl, jcea, mrabarnett, sjmachin, terry.reedy |
| Date | 2012年02月04日.03:08:51 |
| SpamBayes Score | 0.005913337 |
| Marked as misclassified | No |
| Message-id | <1328324932.36.0.327062416186.issue13899@psf.upfronthosting.co.za> |
| In-reply-to |
| Content | |
|---|---|
This should answer that question: >>> re.findall(r"[\A\C]", r"\AC") ['C'] >>> regex.findall(r"[\A\C]", r"\AC") ['A', 'C'] The behaviour of regex is intended to match that of re for backwards compatibility. |
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| History | |||
|---|---|---|---|
| Date | User | Action | Args |
| 2012年02月04日 03:08:52 | mrabarnett | set | recipients: + mrabarnett, georg.brandl, terry.reedy, jcea, sjmachin, ezio.melotti, docs@python |
| 2012年02月04日 03:08:52 | mrabarnett | set | messageid: <1328324932.36.0.327062416186.issue13899@psf.upfronthosting.co.za> |
| 2012年02月04日 03:08:51 | mrabarnett | link | issue13899 messages |
| 2012年02月04日 03:08:51 | mrabarnett | create | |