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Hi,
when a default is specified for a file argument that is open with writing permission (FileType('w')), the default file is always created even if the argument is specified in the command line. 
For example he code:
import argparse 
parser = argparse.ArgumentParser() 
parser.add_argument( 
"-o", 
default = 'fake', 
dest = 'OutputFile', 
type = argparse.FileType('w') 
) 
args = parser.parse_args() 
will create the empty file "fake" even if the -o option is given. 
The value inside the code of args.Outputfile is not affected.
Paolo