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Author mark.dickinson
Recipients amaury.forgeotdarc, eric.smith, mark.dickinson, pitrou, rhettinger, stutzbach
Date 2010年10月07日.21:22:02
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Message-id <1286486523.86.0.587248442341.issue10044@psf.upfronthosting.co.za>
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See the example above: suppose that a compiler is looking at a (p >= q) comparison of pointers. Suppose furthermore that in a particular case that compiler is smart enough to figure out that q is a pointer to the start of an array. Then the compiler is *permitted to assume* that p also points into the same array, since if it didn't then the code would introduce undefined behaviour. And since q is the start of the array, and p is (by assumption) a pointer into the same array, p >= q will automatically be true, so the compiler is free to replace the expression with the integer '1' (i.e., true).
gcc does similar things with checks like (x + 1 > x): if x is a (signed) int, then gcc can and will optimize (x + 1 > x) to 'true', on the basis that x + 1 can never overflow, because such overflow would be undefined behaviour and therefore can't occur in a valid C program.
History
Date User Action Args
2010年10月07日 21:22:03mark.dickinsonsetrecipients: + mark.dickinson, rhettinger, amaury.forgeotdarc, pitrou, eric.smith, stutzbach
2010年10月07日 21:22:03mark.dickinsonsetmessageid: <1286486523.86.0.587248442341.issue10044@psf.upfronthosting.co.za>
2010年10月07日 21:22:02mark.dickinsonlinkissue10044 messages
2010年10月07日 21:22:02mark.dickinsoncreate

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