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classification
Title: String double quoted fatal problem
Type: compile error Stage:
Components: Library (Lib) Versions: Python 2.6
process
Status: closed Resolution: not a bug
Dependencies: Superseder:
Assigned To: Nosy List: amaury.forgeotdarc, cliffdover88
Priority: normal Keywords:

Created on 2008年10月21日 20:10 by cliffdover88, last changed 2022年04月11日 14:56 by admin. This issue is now closed.

Messages (2)
msg75038 - (view) Author: Felipe (cliffdover88) Date: 2008年10月21日 20:10
Hi
I have a problem with python 2.6, when i try to process strings with
triple-quoted string literal i get an error:
a='a''a' #1 double quoted Ok
a='a''''a' # 2 Ok
a= 'a''''''a' # 3 doble quoted -- SyntaxError: EOF while scanning
triple-quoted string literal
a= 'a''''''''a' # 4 ok
a='a''''''''''a' # 5 same error impair doble quoted
a='a''''''''''''a' # 6 Ok...............
a... #7 error..................
msg75047 - (view) Author: Amaury Forgeot d'Arc (amaury.forgeotdarc) * (Python committer) Date: 2008年10月21日 21:05
All your samples explain easily if you consider that two adjacent string 
literals are joined together. (You seem to consider that "double quote" 
is a way to insert a quote character. It's not; Python is not Pascal or 
SQL)
Your first two examples become:
a='a''a' two adjacent strings == 'aa'
a='a''''a' three adjacent strings ('a' + '' + 'a') == 'aa'
The third is an error:
a='a''''''a' one string ('a') followed by the beginning of a "triple 
quoted string" (''') which content starts with the characters (''a') but 
does not have a matching (''') to finish the string, hence the Syntax 
error.
... and so on. Please have a look at http://docs.python.org/reference/lexical_analysis.html#string-literals 
History
Date User Action Args
2022年04月11日 14:56:40adminsetgithub: 48414
2008年10月21日 21:05:19amaury.forgeotdarcsetstatus: open -> closed
resolution: not a bug
messages: + msg75047
nosy: + amaury.forgeotdarc
2008年10月21日 20:10:24cliffdover88create

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