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if the same class name is used within a module, but defined in different contexts (either class in class or class in function), inspect.getsourcelines() on the class object ignores the object context and only returns the first matched name.
reproduce:
a.py
----
class A(object):
 class B(object):
 pass
class C(object):
 class B(object):
 pass
------------------
>>> import inspect
>>> import a
>>> inspect.getsourcelines(a.C.B)
([' class B(object):\n', ' pass\n'], 2)

according to inspect.py line 675 - this is only a best effort.
is this intended?
inspect.py @ 672
 if isclass(object):
 name = object.__name__
 pat = re.compile(r'^(\s*)class\s*' + name + r'\b')
 # make some effort to find the best matching class definition:
 # use the one with the least indentation, which is the one
 # that's most probably not inside a function definition.
 candidates = []
 for i in range(len(lines)):
 match = pat.match(lines[i])
 if match:
 # if it's at toplevel, it's already the best one
 if lines[i][0] == 'c':
 return lines, i
 # else add whitespace to candidate list
 candidates.append((match.group(1), i))
 if candidates:
 # this will sort by whitespace, and by line number,
 # less whitespace first
 candidates.sort()
 return lines, candidates[0][1]
 else:
 raise OSError('could not find class definition')

Inspect could probably be updated to use 3.3's __qualname__ in the case of classes-in-classes; classes-in-functions or functions-in-functions would likely be harder, but I'm not sure it's impossible.

Added Yury (inspect module) and Antoine (PEP 3155) to nosy -- apologies if you're not interested.

I think this was fixed under issue35113.

Thanks iritkatriel for triaging. I can confirm it's fixed with the linked issue. Closing it as duplicate.
./python
Python 3.10.0a0 (heads/master:2b05361bf7, Sep 19 2020, 04:38:05) 
[GCC 7.5.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import inspect, a
>>> inspect.getsourcelines(a.C.B)
([' class B(object):\n', ' pass\n'], 6)