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Title: [CVE-2015-2104] Urlparse insufficient validation leads to open redirect
Type: security Stage:
Components: Library (Lib) Versions: Python 3.7, Python 3.6, Python 3.5, Python 2.7
process
Status: open Resolution:
Dependencies: 22852 Superseder:
Assigned To: Nosy List: PaulMcMillan, benjamin.peterson, christian.heimes, epicfaace, martin.panter, orsenthil, pitrou, python-dev, soilandreyes, vstinner, yaaboukir, ztane
Priority: normal Keywords:

Created on 2015年02月24日 00:11 by yaaboukir, last changed 2022年04月11日 14:58 by admin.

Messages (22)
msg236470 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年02月24日 00:11
The module urlparse lacks proper validation of the input leading to open redirect vulnerability.
The issue is that URLs do not survive the round-trip through `urlunparse(urlparse(url))`. Python sees `/////foo.com` as a URL with no hostname or scheme and a path of `//foo.com`, but when it reconstructs the URL after parsing, it becomes `//foo.com`.
This can be practically exploited this way : http://example.com/login?next=/////evil.com
The for fix this would be for `urlunparse()` to serialize paths with two leading slashes as '/%2F', at least when `scheme` and `netloc` are empty.
msg236471 - (view) Author: Martin Panter (martin.panter) * (Python committer) Date: 2015年02月24日 00:35
Perhaps you actually meant four input slashes, producing two output slashes. That seems more of a bug to me:
>>> urlparse("////foo.com")
ParseResult(scheme='', netloc='', path='//foo.com', params='', query='', fragment='')
>>> urlunparse(_)
'//foo.com'
Solving Issue 22852, which proposes some flags including "has_netloc" on the ParseResult object, might help with this.
msg236472 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年02月24日 00:39
Yes! forgive my mistake I meant four slashes.
msg237088 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年03月02日 22:35
For your information, this security issue has been assigned a CVE ID : CVE-2015-2104
msg237090 - (view) Author: STINNER Victor (vstinner) * (Python committer) Date: 2015年03月02日 23:54
> This can be practically exploited this way : http://example.com/login?next=/////evil.com
Can you please elaborate on the "exploit" part? 
In Firefox, the "////etc/passwd" link shows me my local file /etc/passwd. Ok, but how is it an issue?
"//etc/passwd" also shows me file:////etc/passwd.
The OWASP article on Open Redirect shows example to redirect to a different website. Can you should an example how redirect to a website and not a file:// URL?
https://www.owasp.org/index.php/Open_redirect 
msg237093 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年03月03日 00:04
Yes, exploiting this bug an attacker may redirect a specific vitim to a malicious website, in our case evil.com
>>> x = urlparse("////evil.com")
///evil.com will be parsed as relative-path URL which is the correct expected behaviour
>>> print x
>>> ParseResult(scheme='', netloc='', path='//evil.com', params='', query='', fragment='')
As you see two slashes are removed and it is marked as a relative-path URL but when we reconstruct the URL using urlunparse() function, the URL is treated as an absolute URL to which you will be redirected.
>>> x = urlunparse(urlparse("////evil.com"))
>>> urlparse(x)
ParseResult(scheme='', netloc='evil.com', path='', params='', query='', fragment='')
msg237096 - (view) Author: STINNER Victor (vstinner) * (Python committer) Date: 2015年03月03日 00:11
>>> urlparse("//evil.com")
ParseResult(scheme='', netloc='evil.com', path='', params='', query='', fragment='')
I see evil.com in the netloc field, ok. But Firefox doesn't use Python to parse and url, and typing //evil.com in the address bar converts the address to file:////evil.com. Not a website, but a local file.
So I don't understand the redirection part. Could you maybe write a vulnerable CGI script to demonstrate the bug?
I wrote the following HTML file to try to understand the bug, but I was only able to show the content of my local file /etc/issue:
<head>
 <META http-equiv="refresh" content="5;URL=////etc/issue">
</head>
<p><a href="////etc/issue">issue</a></p>
msg237097 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年03月03日 00:21
When you directly type //evil.com or ////evil.com in Firefox URL bar you will be redirect to evil.com and that is very known, read this : 
http://homakov.blogspot.com/2014/01/evolution-of-open-redirect-vulnerability.html
Here is a video demonstration of the vulnerability : http://youtu.be/l0uDAqpRPpo 
msg237106 - (view) Author: Martin Panter (martin.panter) * (Python committer) Date: 2015年03月03日 05:16
Do you think it would be enough to ensure the urlparse() result remembers whether the empty "//" was present or not? In other words, something like the following mockup (based on the Issue 22852 proposal). An example vunerable program would help me understand this as well.
>>> urlparse("////evil.com")
ParseResult(scheme="", netloc="", has_netloc=True, path="//evil.com", ...)
>>> urlunparse(_)
"////evil.com"
Or would we still need special handling of a path that starts with a double slash despite that; either URL-encoding the second slash, or maybe just raising an exception? Consider that the components are already supposed to be URL-encoded, and you can still generate unexpected valid URLs by giving other invalid components, such as
>>> urlunparse(("", "netloc/with/path", "/more/path", "", "", ""))
'//netloc/with/path/more/path'
msg237149 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年03月03日 16:08
I am not quiet sure about the first proposal but I strongly believe the appropriate method to fix this is by checking if the path starts with double slashes and then URL encoding the two leading slashes.
msg237164 - (view) Author: Paul McMillan (PaulMcMillan) * Date: 2015年03月03日 21:51
While some websites may use urlunparse(urlparse(url)) to validate a url, this is far from standard practice. Django, for instance, does not use this method. While I agree we should clean this behavior up, this is not a vulnerability in core python, and we need to invalidate the assigned CVE.
msg237200 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年03月04日 18:41
"Following the syntax specifications in RFC 1808, urlparse recognizes a netloc 
only if it is properly introduced by ‘//’. Otherwise the input is presumed to be 
a relative URL and thus to start with a path component." 
https://docs.python.org/2/library/urlparse.html
2015年03月03日 22:16 GMT+00:00 Paul McMillan <>:
 Yeah. I agree the lack of round trip is surprising, and I agree we
 should fix it.
 I think the underlying issue here is that urlparse has a pretty
 different view of the world when compared with the browsers. I know
 that bit me when I first started using python, and it periodically
 surfaces in cases like this, where the browser thinks that
 "//evil.com" is a url, but we've parsed it as part of a path.
 Backwards compatibility makes it hard to update urlparse to precisely
 match browser behavior, but there's probably room for a new library
 designed with browser compatibility as a primary feature.
 -Paul
 On Tue, Mar 3, 2015 at 10:07 PM, Antoine Pitrou <> wrote:
 >
 > Hi Paul,
 >
 > Le 03/03/2015 23:01, Paul McMillan a écrit :
 >> I understand how this works. You don't need to paste the example again.
 >>
 >> The documentation makes no guarantee that parse/unparse will do what
 >> you want them to do, and does explicitly lay out the specific rules
 >> used for separating the parts.
 >
 > Well, I don't know if it's a security issue, but failure to roundtrip
 > *is* surprising (and IMHO dangerous for that reason) behaviour to say
 > the least.
 >
 > Moreover, the urlunparse() documentation (in 3.x) says:
 > """
 > Construct a URL from a tuple as returned by urlparse(). [...] This may
 > result in a slightly different, but equivalent URL, if the URL that was
 > parsed originally had unnecessary delimiters
 > """
 > 
(https://docs.python.org/3/library/urllib.parse.html#urllib.parse.urlunparse)
 >
 > which implies that any divergence when roundtripping should only consist
 > in cosmetic, not essential, differences ("equivalent URL").
 >
 > Regards
 >
 > Antoine.
 > -----------------------------
 > Python Security Response Team
 > Unsubscribe: https://mail.python.org/mailman/options/psrt/paul
%40mcmillan.ws
msg237411 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年03月07日 02:53
From: cve-assign () mitre org
Date: Thu, 5 Mar 2015 16:42:02 -0500 (EST)
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
We think that the issue reduces to the question of whether it's
acceptable for urlparse to provide inconsistent information about the
structure of a URL.
https://docs.python.org/2/library/urlparse.html says:
 urlparse.urlparse(urlstring[, scheme[, allow_fragments]])
 Parse a URL into six components, returning a 6-tuple. This
 corresponds to the general structure of a URL:
 scheme://netloc/path;parameters?query#fragment.
 urlparse.urlunparse(parts)
 Construct a URL from a tuple as returned by urlparse(). The parts
 argument can be any six-item iterable. This may result in a
 slightly different, but equivalent URL, if the URL that was parsed
 originally had unnecessary delimiters (for example, a ? with an
 empty query; the RFC states that these are equivalent).
The first issue is that the urlunparse documentation is ambiguous. We
believe the reasonable interpretation is that there is a missing third
sentence: "This ALWAYS results in a URL that is either identical or
equivalent to the URL that was parsed originally." There's another
interpretation that we believe is unreasonable: "This may result in a
slightly different, but equivalent URL, if the URL that was parsed
originally had unnecessary delimiters. If the URL that was parsed
originally did not have unnecessary delimiters, then the behavior of
urlunparse is UNDEFINED."
So, our expectation is that urlunparse(urlparse(original_url)) should
not have any significant effect on the meaning of original_url. We
also think that a Python user should be able to rely on that property
to make security-relevant decisions. To simply the situation, consider
a case where the URL is used exclusively within Python code, and is
never accessed by any web browser.
The actual behavior is:
 >>> from urlparse import urlparse, urlunparse
 >>> print urlparse("////example.com")
 ParseResult(scheme='', netloc='', path='//example.com', params='', query='', fragment='')
 >>> print urlparse(urlunparse(urlparse("////example.com")))
 ParseResult(scheme='', netloc='example.com', path='', params='', query='', fragment='')
 >>> print urlparse(urlunparse(urlparse(urlunparse(urlparse("////example.com")))))
 ParseResult(scheme='', netloc='example.com', path='', params='', query='', fragment='')
Here, urlparse(urlunparse(original_url)) does have a significant
effect on the meaning of original_url. The Python user may have wanted
to make a security-relevant decision based on whether netloc was an
empty string. However, netloc is different depending on whether
urlparse(urlunparse(original_url)) occurs at least once. The user's
application (suppose it's called "PyNetlocExaminer") is affected in a
security-relevant way.
The next question is, if there is a CVE for a report of a
security-relevant problem, what product is named as the primary
affected product within that CVE. There is no perfect answer to this
question. Especially in the case of a general-purpose language such as
Python, there's an extremely wide range of bugs that might become
security-relevant in some applications. What we usually try to do is
make the CVE useful to users who may need to perform a software
update. Specifically:
 1. If the language implementation is not ever going to be changed
 (for example: because the language maintainer believes the
 observed behavior has always been correct, or the language
 maintainer believes that it has retroactively become correct
 because any change would break compatibility with other
 applications), then the application is named as the primary
 affected product in the CVE. In other words, if the inconsistency
 between netloc='' and netloc='example.com' were actually the
 intended behavior all along, then PyNetlocExaminer would be named
 in the CVE. Here, realistically, the end user would need to
 update or manually fix PyNetlocExaminer.
 2. If the language implementation is incorrect and is planned to be
 changed at some point, and that would eliminate the
 security-relevant problem, then the language implementation is
 named in the CVE. (An application might also be named in the CVE,
 especially if there are very few affected applications.) This
 option occurs regardless of whether the language maintainer
 believes that it is a language vulnerability. (The language
 maintainer has the option of composing a dispute that would be
 appended to the CVE.) Here, the end user may ultimately decide to
 address the problem by updating their Python installation, not by
 updating PyNetlocExaminer.
Again, this is imperfect. It works best in the relatively common case
where a language bug has security relevance in many applications. It
might work especially poorly in a case where a language bug has
security relevance in exactly one application. However, it seems
preferable to do the above consistently, rather than make the outcome
depend on application populations, or depend on reaching universal
agreement about what code should have been written differently.
- -- 
CVE assignment team, MITRE CVE Numbering Authority
M/S M300
202 Burlington Road, Bedford, MA 01730 USA
[ PGP key available through http://cve.mitre.org/cve/request_id.html ]
msg237412 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年03月07日 02:55
From: Amos Jeffries <squid3 () treenet co nz>
Date: 2015年3月06日 14:09:55 +1300
On 6/03/2015 10:42 a.m., cve-assign () mitre org wrote:
 We think that the issue reduces to the question of whether it's
 acceptable for urlparse to provide inconsistent information about the
 structure of a URL.
 https://docs.python.org/2/library/urlparse.html says:
 urlparse.urlparse(urlstring[, scheme[, allow_fragments]])
 Parse a URL into six components, returning a 6-tuple. This
 corresponds to the general structure of a URL:
 scheme://netloc/path;parameters?query#fragment.
My 2c ... no it does not.
There are 7 parts in a URL. What is called "netloc" in that description
is actually two fields: [userinfo '@'] authority
The userinfo field is very much alive and well in non-HTTP schemes.
Ignoring the userinfo field leaves implementations open to attacks of
the form:
 scheme://example.com () phishing com/path
AYJ
msg240191 - (view) Author: Yassine ABOUKIR (yaaboukir) Date: 2015年04月06日 21:54
Any updates concerning this issue ? is it going to be fixed or at least modify the documentation in order to warn developers about this behaviour ?
msg240207 - (view) Author: Martin Panter (martin.panter) * (Python committer) Date: 2015年04月07日 13:18
FYI I posted a patch at Issue 22852 to retain the empty netloc "//" when appropriate. But even if there is interest in that patch, I guess it can still only be applied to the next version of Python (3.5 or whatever), being a new feature.
Maybe you could suggest some wording or a patch to the documentation that could be applied to bugfix releases as well.
msg240237 - (view) Author: Paul McMillan (PaulMcMillan) * Date: 2015年04月07日 23:02
As Martin said, backporting a change for this wouldn't be appropriate
for Python 2.7. The 2.7 docs could certainly be updated to make this
clearer, but we can't introduce a breaking change like that to the
stable release.
msg277328 - (view) Author: Christian Heimes (christian.heimes) * (Python committer) Date: 2016年09月24日 19:11
What's the verdict on this bug? It's been dangling for almost one and half year.
msg277342 - (view) Author: Martin Panter (martin.panter) * (Python committer) Date: 2016年09月24日 23:24
It is not clear what Yassine’s bug is. Maybe it is about round-tripping from urlparse() → urlunparse(). If so, it could be solved by fixing either of the following two problems:
1. urlunparse() forgets the initial pair of slashes when netloc="". That might be addressed by Issue 22852, and documented as a limitation in the mean time.
2. urlunparse() accepts invalid components, such as netloc="", path="//evil.com", which transforms the path into a hostname. Yassine preferred to percent-encode the path and pass it through, though I think an exception would be more sensible. Or just documenting that there is little or no validation.
When considering the second problem of validation, you have to be aware that urlunparse() is documented to handle schemes like "mailto:" not listed in "uses_netloc". According to RFC 6068, mailto://evil.com is valid syntax, and is decoded to netloc="", path="//evil.com". In this case, netloc="evil.com" would probably be invalid instead.
msg277350 - (view) Author: Antti Haapala (ztane) * Date: 2016年09月25日 08:56
The problem is in `urlunparse`. If you check the RFC 2396, it has the following regular expression:
 ^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?
where group 3 is the //netloc, and 4 is netloc substring, of an url http://netloc/foobar - and this is what Python should use to parse an URI using RFC 2396... but:
 >>> pat.fullmatch('////netloc').group(4)
 ''
 >>> pat.fullmatch('/relative').group(4)
 >>> 
Someone took the shortcut. no netloc is different from netloc being the empty string '', but 
 >>> urlparse('////netloc')
 ParseResult(scheme='', netloc='', path='//netloc', params='', query='', fragment='')
 >>> urlparse('/netloc')
 ParseResult(scheme='', netloc='', path='/netloc', params='', query='', fragment='')
In the latter parsing result netloc should be *None*. Unfortunately I believe it is too late to change this either way.
msg277354 - (view) Author: Antti Haapala (ztane) * Date: 2016年09月25日 09:56
*I mean the problem exists in `urlparse`, not only in `urlunparse`
msg322676 - (view) Author: Martin Panter (martin.panter) * (Python committer) Date: 2018年07月30日 13:15
Issue 34276 was opened about a similar case for "file:" URLs. I believe both "file:" scheme and no-scheme cases are a regression and could be fixed by adding another pair of slashes (an empty "netloc" part):
>>> urlparse("////foo.com") # No change
ParseResult(scheme='', netloc='', path='//foo.com', params='', query='', fragment='')
>>> urlunparse(_) # Knows to escape slashes with another double-slash
'////foo.com'
History
Date User Action Args
2022年04月11日 14:58:13adminsetgithub: 67693
2019年10月24日 10:32:56vstinnersettitle: Urlparse insufficient validation leads to open redirect -> [CVE-2015-2104] Urlparse insufficient validation leads to open redirect
2019年08月15日 03:25:12epicfaacesetnosy: + epicfaace
2018年07月30日 13:15:46martin.pantersetmessages: + msg322676
2016年09月25日 09:56:10ztanesetmessages: + msg277354
2016年09月25日 08:56:18ztanesetnosy: + ztane
messages: + msg277350
2016年09月24日 23:24:37martin.pantersetdependencies: + urllib.parse wrongly strips empty #fragment, ?query, //netloc
messages: + msg277342
2016年09月24日 19:11:23christian.heimessetnosy: + christian.heimes

messages: + msg277328
versions: + Python 3.7, - Python 3.2, Python 3.3, Python 3.4
2015年04月07日 23:02:21PaulMcMillansetmessages: + msg240237
2015年04月07日 13:18:19martin.pantersetmessages: + msg240207
2015年04月06日 21:54:29yaaboukirsetmessages: + msg240191
2015年03月11日 01:46:49martin.panterlinkissue1722348 superseder
2015年03月07日 02:55:10yaaboukirsetmessages: + msg237412
2015年03月07日 02:53:11yaaboukirsetmessages: + msg237411
2015年03月04日 18:41:29yaaboukirsetmessages: + msg237200
2015年03月03日 21:51:30PaulMcMillansetnosy: + PaulMcMillan
messages: + msg237164
2015年03月03日 16:08:33yaaboukirsetmessages: + msg237149
2015年03月03日 05:16:51martin.pantersetmessages: + msg237106
2015年03月03日 00:21:44yaaboukirsetmessages: + msg237097
2015年03月03日 00:11:47vstinnersetmessages: + msg237096
2015年03月03日 00:04:30yaaboukirsetmessages: + msg237093
2015年03月02日 23:54:15vstinnersetnosy: + vstinner
messages: + msg237090
2015年03月02日 22:35:45yaaboukirsetmessages: + msg237088
2015年02月28日 20:11:59yaaboukirsetnosy: + pitrou, benjamin.peterson, python-dev
2015年02月24日 01:27:57yaaboukirsetnosy: + orsenthil, soilandreyes
2015年02月24日 00:39:15yaaboukirsetmessages: + msg236472
2015年02月24日 00:35:49martin.pantersetnosy: + martin.panter
messages: + msg236471
2015年02月24日 00:13:00yaaboukirsetversions: + Python 2.7, Python 3.2, Python 3.3, Python 3.4, Python 3.5, Python 3.6
2015年02月24日 00:11:53yaaboukircreate

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