Print 2 numbers stored in 24-bits in decimal format
An implementation function from the nice little Wiegand library YetAnotherArduinoWiegandLibrary prints a hexadecimal representation of a facility # & card # (8-bit facility #, 16-bit card #) — 24 bits of a 26-bit stream that comes across the wire.
Example encoded 24-bit number: 7111097 (decimal). Hex equivalent: 6C81B9. The 6C portion is the facility # (decimal: 108). 81B9 is card # (decimal 33209).
This function from the library's example usage serial prints the hexadecimal format of the number:
void receivedData(uint8_t* data, uint8_t bits, const char* message) {
Serial.print(message);
Serial.print(bits);
Serial.print("bits / ");
//Print value in HEX
uint8_t bytes = (bits+7)/8;
for (int i=0; i<bytes; i++) {
Serial.print(data[i] >> 4, 16); //1st, 3rd, 5th hex digit
Serial.print(data[i] & 0xF, 16); //2nd, 4th, 6th hex digit
}
Serial.println();
}
What I've tried to do unsuccessfully so far is to loop over the bits to also serial print the two decimal formatted numbers in the final output form: 108:33209
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