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edited May 23, 2017 at 12:37

Sorry guys, I made a very silly mistake here, i was using Serial.print here in ISR, following the Slave_Receiver example in the Arduino examples. I got a bit carried away with the use of those Serial debug messages and added lots of them,

I got this info from http://stackoverflow.com/questions/17985830/arduino-using-interrupts-freezes-processing-and-serial-output https://stackoverflow.com/questions/17985830/arduino-using-interrupts-freezes-processing-and-serial-output

checkout answer by elias

The code does not freeze now. Sorry for the troubles, i hope this helps someone else in return.

I got this info from http://stackoverflow.com/questions/17985830/arduino-using-interrupts-freezes-processing-and-serial-output

checkout answer by elias

The code does not freeze now. Sorry for the troubles, i hope this helps someone else in return.

I got this info from https://stackoverflow.com/questions/17985830/arduino-using-interrupts-freezes-processing-and-serial-output

checkout answer by elias

The code does not freeze now. Sorry for the troubles, i hope this helps someone else in return.

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answered Dec 6, 2014 at 11:17

ArunMKumar

answered Dec 6, 2014 at 11:17

ArunMKumar

I got this info from http://stackoverflow.com/questions/17985830/arduino-using-interrupts-freezes-processing-and-serial-output

checkout answer by elias

The code does not freeze now. Sorry for the troubles, i hope this helps someone else in return.