Timeline for Multiple LEDs & HC-SR04
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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Jun 15, 2015 at 15:36 | vote | accept | user2969 | ||
Jun 15, 2015 at 15:33 | comment | added | user2969 | Thanks Everyone! That answers my question. Sorry for all the confusions | |
Jun 15, 2015 at 14:37 | comment | added | Edgar Bonet | 140 mA × (9 V − 5 V) = 0.56 W. The regulator can dissipate up to 0.6 W with the minimum pad size. Then, assuming the Arduino complies with this required minimum, you should be (barely) fine. | |
Jun 15, 2015 at 13:51 | comment | added | Anonymous Penguin | @user2969 If you hooked the power to VIN and GND, then that should be more than enough for the HC-SR04 and a handful of LEDs. On a side note, please ask another question if you have another question. Thanks! | |
Jun 15, 2015 at 13:04 | comment | added | user2969 | Edgar, would I have enough current to run those LEDs and a distance sensor from the 5 v pin if I had a 9v 1A charger? | |
Jun 15, 2015 at 7:59 | comment | added | Edgar Bonet | If you power your Arduino through the Vin pin, the current limit will be given by the 5 V regulator. According to it's datasheet, it's actually a power dissipation limit: the higher the Vin voltage, the lower the current limit (power = current × (Vin − 5 V)). Check the thermal pad size on your Arduino and refer to Fig. 21 (p. 8) of the datasheet. | |
Jun 15, 2015 at 5:50 | comment | added | user2969 | Thanks for all your help and encouragement. The link arduino.cc/en/Main/ArduinoBoardUno says that there is a 5 v output straight from the board's voltage regulator. Is that not separate from the output pins? | |
Jun 15, 2015 at 3:38 | history | edited | user2969 | CC BY-SA 3.0 |
added 50 characters in body
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Jun 15, 2015 at 3:29 | answer | added | Kolban | timeline score: 0 | |
Jun 15, 2015 at 3:12 | review | First posts | |||
Jun 15, 2015 at 15:38 | |||||
Jun 15, 2015 at 3:11 | history | asked | user2969 | CC BY-SA 3.0 |