Suppose I have an InputStream
that contains text data, and I want to convert this to a String
(for example, so I can write the contents of the stream to a log file).
What is the easiest way to take the InputStream
and convert it to a String
?
public String convertStreamToString(InputStream is) {
// ???
}
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5possible duplicate of In Java how do a read an input stream in to a string?Rob Hruska– Rob Hruska2010年08月13日 18:24:20 +00:00Commented Aug 13, 2010 at 18:24
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Agree. I've voted to close this as duplicate and edited the other question to include some of the title keywords and question text from here.Daniel Fortunov– Daniel Fortunov2010年08月17日 09:26:46 +00:00Commented Aug 17, 2010 at 9:26
6 Answers 6
If you want to do it simply and reliably, I suggest using the Apache Jakarta Commons IO library IOUtils.toString(java.io.InputStream, java.lang.String)
method.
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1This is the short and sweet way.Kushal Paudyal– Kushal Paudyal2009年11月19日 15:20:29 +00:00Commented Nov 19, 2009 at 15:20
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3The only downside to this is that you need to take an external dependency in this library, which may not always be desired.Daniel Fortunov– Daniel Fortunov2009年11月19日 16:20:21 +00:00Commented Nov 19, 2009 at 16:20
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1You need to specify the encoding too, otherwise it will use the platform default, which is anything but reliable.Christoffer Hammarström– Christoffer Hammarström2011年03月10日 15:25:06 +00:00Commented Mar 10, 2011 at 15:25
This is my version,
public static String readString(InputStream inputStream) throws IOException {
ByteArrayOutputStream into = new ByteArrayOutputStream();
byte[] buf = new byte[4096];
for (int n; 0 < (n = inputStream.read(buf));) {
into.write(buf, 0, n);
}
into.close();
return new String(into.toByteArray(), "UTF-8"); // Or whatever encoding
}
String text = new Scanner(inputStream).useDelimiter("\\A").next();
The only tricky is to remember the regex
\A
, which matches the beginning of input. This effectively tellsScanner
to tokenize the entire stream, from beginning to (illogical) next beginning...
- from the Oracle Blog
Since Java 9 InputStream.readAllBytes() even shorter:
String toString(InputStream inputStream) throws IOException {
return new String(inputStream.readAllBytes(), StandardCharsets.UTF_8); // Or whatever encoding
}
Note: InputStream is not closed in this example.
You can use a BufferedReader
to read the stream into a StringBuilder
in a loop, and then get the full contents from the StringBuilder
:
public String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
Full disclosure: This is a solution I found on KodeJava.org. I am posting it here for comments and critique.
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2Keep in mind that the BufferedReader constructor you're using assumes the platform default text encoding on the bytes coming from the InputStream, which will probably be wrong. You must know the encoding and specify it in the Reader constructor.Jonathan Feinberg– Jonathan Feinberg2009年11月19日 14:51:43 +00:00Commented Nov 19, 2009 at 14:51
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4By using this constructor, you tell the InputStreamReader to use the default platform encoding, wich should be avoided. You should specify the charset the data is encoded in so it gets correctly decoded using one of the other three constructors.Sylar– Sylar2009年11月19日 14:54:34 +00:00Commented Nov 19, 2009 at 14:54
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2It's also unnecessary effort to use a BufferedReader to split the input on line breaks, just to add the line breaks manually to the StringBuilder and almost a WTF to actually use a StringBuilder to prevent String object creation, but then call append(line + "\n") instead of append(line).append("\n"). Closing the InputStream is also not particularly clever.jarnbjo– jarnbjo2009年11月19日 15:49:07 +00:00Commented Nov 19, 2009 at 15:49
A nice way to do this is using Apache commons IOUtils
IOUtils.toString(inputStream, string);