Fw: Fw: Re: [Antennas] 450 Ohm Ladder Line
George, W5YR
[email protected]
2002年12月14日 19:22:55 -0600
A single wave traveling down a transmission line has its
voltage/current ratio determined by the Zo of the line. A low Zo
involves a lower voltage at a higher current to convey the same power
than does a high Zo line with higher voltage and lower current. Since
most line loss at HF is I^2R loss in the line conductors, the higher
Zo with its lower current will evidence less line loss that a lower Zo
line such as coax or closely spaced open wire line.
I am not at all sure how to interpret your comment/question, but yes
for a given power level the current in the line is determined by the
Zo which in turn, depending upon the conductor size, material, etc.
determines the line I^2R loss.
So, I suppose that low Zo open-wire line would do a better job of
keeping your coffee warm than 600 ohm line! <:}
73/72, George
Amateur Radio W5YR - the Yellow Rose of Texas
In the 57th year and it just keeps getting better!
Fairview, TX 30 mi NE of Dallas in Collin county EM13qe
K2 #489 IC-765 #2349 IC-756 PRO #2121 IC-756 PRO2 #03235
----- Original Message -----
From: "David J. Windisch" <[email protected]>
To: <[email protected]>
Sent: Saturday, December 14, 2002 5:09 AM
Subject: Re: Fw: Fw: Re: [Antennas] 450 Ohm Ladder Line
> Did I miss something?
>> Conductors, whether in a feedline or *whatever*, dissipate power
according
> to the usual formulae, not at, eg, the feedline's Z, right?
>> Imagine a 50-ft piece of OWL coiled on your desk bosun's style,
dissipating
> 300W of r-f or whatever.
>> Would it warm up your cuppa iced coffee?
>> 73, Dave, N3HE