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'/bin/sh -c' with multiple args
Hey,
How does '/bin/sh -c' with multiple args actually
work?
The manual page says
sh -c command_string [command_name [argument ...]]
is valid, and should behave as such:
"Read commands from the command_string operand instead
of, or in addition to, from the standard input.
Special parameter 0 will be set from the command_name
operand if given, and the positional parameters (1, 2,
etc.) set from the remaining argument operands, if
any."
So I would expect
sh -c /bin/sleep whatever 30
to lead to "/bin/sleep 30" being invoked with an argv0
set to "whatever".
However:
$ sh -c /bin/sleep whatever 30
usage: sleep seconds
Now I know that I can do
$ sh -c "/bin/sleep 30"
but the manual page suggests I should be able to set
argv0 of the command as described above, but I don't
see a way of actually doing that.
What am I missing?
-Jan
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