LPEG: P(fct) seems not to consume input
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- Subject: LPEG: P(fct) seems not to consume input
- From: Dirk Laurie <dirk.laurie@...>
- Date: 2018年10月31日 21:00:17 +0200
I define a function to be used with LPEG that simply returns the first
character. It _cannot_ match the empty string:
function fct(str)
if #str==0 then return false
else return 2,str:sub(1,1)
end
end
I turn it into an LPEG pattern:
lpeg.version() --> 1.0.0
patt=lpeg.P(fct)
"patt" is supposed to do exactly the same as lepg.C(1). It works OK on its own:
patt:match"" --> nil
patt:match"abc" --> a
But I can't make it match twice:
(patt*patt):match"abc" --> a a [expected: a b]
This seems to contradict the manual's statement that: "If the call
returns a number, the match succeeds and the returned number becomes
the new current position."