bug/feature: 'if 1then print"valid syntax!"end' is valid syntax
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- Subject: bug/feature: 'if 1then print"valid syntax!"end' is valid syntax
- From: nobody <nobody+lua-list@...>
- Date: Mon, 8 Aug 2016 20:56:22 +0200
(I strongly suspect this is known and I think I've seen this before
somewhere but couldn't find it in the archive... so here goes (again?):)
Lua 5.3 and 5.2 accept this (Lua 5.1/LuaJIT don't):
_=0_=1._=2local y x=3goto foo x=4while y do end x=5repeat x=6return
7until x::foo::if 8then x=9print'"valid" syntax!'end
Specifically, any char that cannot be part of the number implicitly ends
the token. (That is, the expected ones (space/symbols) *plus* [g-zG-Z_]
with the exception of (1) [xX] in initial '0x' or '0X' (but after two
digits like 00x or 00X it's a "valid" boundary again), and (2) [pP] for
hex literals where an exponent might follow.) Compare
llex.c/read_numeral [1] for the details.
While it exists, it's a nice code golfing tool:
u,v,w,x,y,z=1,2,3,4,5,6
u=1v=2w=3x=4y=5z=6
m=1n=1repeat print(m/n)m,n=m+n,m until m<0
Whether it's worth break^Wfixing is debatable... the simplest fix is
clearly "just don't write it like that!"
-- Marco
[1]: https://www.lua.org/source/5.3/llex.c.html#read_numeral