Re: Use-cases for string.gsub(str, "().", "%1")

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Subject: Re: Use-cases for string.gsub(str, "().", "%1")
From: Fidelis Assis <fidelis.assis@...>
Date: 2015年8月20日 16:25:49 -0300

2015年08月20日 15:57 GMT-03:00 Soni L. <fakedme@gmail.com>:

On 20/08/15 03:54 PM, Fidelis Assis wrote:

Can also be used for expansion of positional notation

s = '1010'
print((string.gsub(s, "()(.)", function (p, d) return ' + ' .. d .. '*2^' .. #s-p end))

+ 1*2^3 + 0*2^2 + 1*2^1 + 0*2^0

and base conversion.

-- Fidelis

Not the same as using it in the replacement string.

You can do that without the function, just ugly.

print ((string.gsub(s, "()(.)", ' + %2*2^(' .. #s ..'-%1)')))

-- Fidelis

References:
- Use-cases for string.gsub(str, "().", "%1"), Soni L.
- Re: Use-cases for string.gsub(str, "().", "%1"), Matthew Wild
- Re: Use-cases for string.gsub(str, "().", "%1"), Soni L.
- Re: Use-cases for string.gsub(str, "().", "%1"), Fidelis Assis
- Re: Use-cases for string.gsub(str, "().", "%1"), Soni L.

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