Parser(?) register allocation
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- Subject: Parser(?) register allocation
- From: "Soni L." <fakedme@...>
- Date: 2015年1月09日 20:41:24 -0200
Hello,
I'm trying to figure out parser register allocation.
So we have OP_SELF A B C R(A+1) := R(B); R(A) := R(B)[RK(C)], it
allocates 2 registers. If I want to change R(A), I need a way to
deallocate it so the next expression(s) can change it.
My question is, how can I deallocate R(A) without deallocating R(A+1)?
So I can get things like:
GETUPVAL 0 0 ; R(0) = _ENV
OP_SELF 1 0 -1 ; R(2) = _ENV; R(1) = _ENV["table"]
OP_GETTABLE 1 1 -2 ; R(1) = R(1) = R(1)["insert"]
LOADK 3 -2 ; R(3) = "test"
OP_CALL 1 3 1 ; R(1)(R(2), R(3))
Using a syntax like:
-- (I actually want this code to output bytecode _exactly_ as above)
local _ENV = _ENV
_ENV:table.insert"test"
--
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