Re: Is there an #include equivalent in Lua (I do not mean require)

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Subject: Re: Is there an #include equivalent in Lua (I do not mean require)
From: Rodrigo Azevedo <rodrigoams@...>
Date: 2014年9月18日 12:04:29 -0300

I use the make! for example, if mod3.lua requires mod1.lua and mod2.lua the simple makefile

all: mod1.luah mod3.luah mod2.luah
        luac -o prog.exe main.lua

mod1.luah: mod1.lua
        cat mod1.lua >> main.lua

mod2.luah: mod2.lua
        cat mod2.lua >> main.lua

mod3.luah: mod1.luah mod2.luah
        cat mod3.lua >> main.lua

clean:
        rm main.lua

solves my problems.

2014年09月18日 10:07 GMT-03:00 Tony Papadimitriou <tonyp@acm.org>:

Hi all,

How can one #include a bunch of files so that when compiled, a single self-contained executable is produced.

'require' does not qualify as equivalent because it needs to find the files at run-time.

TIA
Tony

--
Rodrigo Azevedo Moreira da Silva

Follow-Ups:
- Re: Is there an #include equivalent in Lua (I do not mean require), Milind Gupta

References:
- Module modularity, Geoff Leyland
- Re: Module modularity, Rena
- Re: Module modularity, Geoff Leyland
- RE: Module modularity, Thijs Schreijer
- Re: Module modularity, steve donovan
- Is there an #include equivalent in Lua (I do not mean require), Tony Papadimitriou

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