Re: Lua Parser
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- Subject: Re: Lua Parser
- From: Igor Medeiros <igorosbergster@...>
- Date: 2012年7月17日 22:40:38 -0300
i am sorry for ask something like this, but i did not understand which function of lpeg i should use to parser a string which contains a lua code sample
local code = [[
--some lua code here
]]
i tried print(lpeg.match(lpeg.P(lua), code)) but it prints just the index of first character after the match or nil if the match does not occur
I need a error message like those showed by lua interpreter when it find a syntactic error, instead the nil value printed .
Thanks
Igor
returns the index in the subject of the first character after the match, or the ca
2012年7月17日 Igor Medeiros
<igorosbergster@gmail.com>
Thanks by replies.
Best wishes,
Igor
2012年7月17日 Robert G. Jakabosky
<bobby@sharedrealm.com>
On Tuesday 17, Igor Medeiros wrote:
> Hi,
>
> Are there some lua parser done in lua or C available for download? If there
> exists, could someone tell me where find it?
This page has a Lua Lexer & Lua Parser written in Lua that uses LPeg:
http://lua-users.org/wiki/LpegRecipes
--
Robert G. Jakabosky