filter an array in place
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- Subject: filter an array in place
- From: Emmanuel Oga <emmanueloga@...>
- Date: 2011年1月14日 01:12:40 -0300
Hello, I'm looking for the best proper way of doing this:
local tab = {"a", "a", "c", "a", "d", "a" }
for index, val in ipairs(tab) do
if val == "a" then -- could be any other complex condition
table.remove(tab, index)
end
end
-- WRONG: tab = { "a", "c", "d" }, should be { "c", "d" }
So removing elements from a container _while you are iterating it_ is
wrong in most languages. I'm looking for the nicest and proper way of
doing it.
Two methods I came up with:
1) popping from the array and pushing to a new one if the condition is met.
2) Iterating first, storing indexes to remove, then removing one by
one (compensating index offset as a result of each removed elements)
http://pastie.org/1458808
Is there any other more elegant way?
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