Re: Table compare
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- Subject: Re: Table compare
- From: "Juri Munkki" <jm_list@...>
- Date: 2008年12月30日 16:20:26 +0200 (EET)
Here's something I think might work for the requested case. It makes use
of next to count the items in the table b while it's iterating table a
using pairs (matching order does not matter).
function compareTables(a, b)
local bi = nil;
for k,v in pairs(a) do
bi = next(b, bi);
if v ~= b[k] then
return false;
end
if bi == nil then
return false;
end
end
if next(b, bi) ~= nil then
return false;
end
return true;
end
a = { x = 1, y = 2, z = 3 };
b = { x = 1, y = 2, z = 3 };
c = { x = 1, y = 3, z = 2 };
d = { x = 1, y = 2, z = 3, w = 4 };
e = { x = 1, z = 3, y = 2 };
print(compareTables(a,b), compareTables(a, c), compareTables(a, d),
compareTables(d, a), compareTables(a, e), compareTables({}, {}));