RE: Passing arrays from C++ to LUA
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- Subject: RE: Passing arrays from C++ to LUA
- From: <Andreas.Volz@...>
- Date: 2007年8月27日 17:46:15 +0200
> -----Original Message-----
> From: lua-bounces@bazar2.conectiva.com.br
> [mailto:lua-bounces@bazar2.conectiva.com.br] On Behalf Of
> Shmuel Zeigerman
> Sent: Monday, August 27, 2007 6:27 PM
> To: Lua list
> Subject: Re: Passing arrays from C++ to LUA
>
> > C++:
> > lua_newtable (L);
> > lua_settable (L,1);
> >
> > lua_Integer n = 6;
> > lua_pushinteger (L, n);
>
> Try something like this:
>
> int arr[4] = { 5,100,-20,0 };
> lua_newtable(L); // table
> for (i=0; i<4; i++) {
> lua_pushinteger(L, i+1); // table,key
> lua_pushinteger(L, arr[i]); // table,key,value
> lua_settable(L,-3); // table
> }
Ok, this one works. But my error was another one. I use tolua++ as interface to LUA. But it has not all features I need. So I tried to get my data "through" tolua++. But it seems tolua++ hits me here. If I go into the generated binder code and change "return 0;" to "return 1;" it works. If I use "return 1;" to set the number of results before tolua++ gets the function tolua++ push the "1" onto the stack. But this isn't what I like. :-(
Do you understand the problem?
> ... and read "Programming in Lua" (http://www.lua.org/pil/),
> on-line and free :)
I'm reading this document. Very good!
regards
Andreas
--
Dipl.-Inf. (FH) Andreas Volz, ES1
Elektrobit
Phone: +49 (9131) 7701 167, mailto:Andreas.Volz@elektrobit.com
Fax: +49 (9131) 7701 333, http://www.elektrobit.com
Elektrobit Automotive GmbH, Am Wolfsmantel 46, 91058 Erlangen, Germany
Managing Director Otto Fößel
Register Court Fürth HRB 4886
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