passing vararg to xpcall?
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- Subject: passing vararg to xpcall?
- From: PA <petite.abeille@...>
- Date: 2006年2月22日 21:02:31 +0100
Hello,
I would like to use 'xpcall' in conjunction with 'debug.traceback' to
produce a nice stack trace in case something goes wrong :)
Additionally, I would like to pass some vararg to 'xpcall' as well.
My first attempt looked like this:
function try( ... )
local aFunction = function()
tryToDoIt( ... )
end
local someResults = { xpcall( aFunction, debug.traceback ) }
local aStatus = someResults[ 1 ]
if aStatus == true then
table.remove( someResults, 1 )
return unpack( someResults )
end
return nil, someResults[ 2 ]
end
Unfortunately, accessing vararg from a function which doesn't directly
declare it seems to be frown upon:
lua: TestMeta.lua:298: cannot use '...' outside a vararg function near
'...'
The second try looks like the following, with some additional vararg
packing/unpacking:
function try( ... )
local someArguments = { ... }
local aFunction = function()
tryToDoIt( unpack( someArguments ) )
end
local someResults = { xpcall( aFunction, debug.traceback ) }
local aStatus = someResults[ 1 ]
if aStatus == true then
table.remove( someResults, 1 )
return unpack( someResults )
end
return nil, someResults[ 2 ]
end
This compile fine and produce a nice stack trace as well :)
However, any nil argument get lost in translation during the
packing/unpacking of the vararg :/
Is there a way out of this conundrum beside using 'pcall' (and minus
the valuable stack trace info)?
For the record, I'm using Lua 5.1 (final).
TIA.
Cheers
--
PA, Onnay Equitursay
http://alt.textdrive.com/