Re: xml pull parser
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- Subject: Re: xml pull parser
- From: PA <petite.abeille@...>
- Date: 2005年3月21日 13:54:01 +0100
On Mar 21, 2005, at 13:22, Adam D. Moss wrote:
Actually I just noticed that you have a similar problem with
&#XXX; entities which can't be solved with merely re-ordering
the substitutions. But you can fold every &*; case into the
aFunction and be happy (likely somewhat faster too).
Well... not sure about happiness... but is the current concoction:
-- class method to decode a given string
thisClass.decode = function( aString )
if ( aString ~= nil ) then
local aFunction = function( aValue )
if ( aValue == "lt" ) then
return "<"
elseif ( aValue == "gt" ) then
return ">"
elseif ( aValue == "apos" ) then
return "'"
elseif ( aValue == "quot" ) then
return "\""
elseif ( string.sub( aValue, 1, 1 ) ==
"#" ) then
local aNumber = tonumber(
string.sub( aValue, 2 ) )
if ( ( aNumber ~= nil ) and (
aNumber > 0 ) and ( aNumber < 255 ) ) then
return string.char(
aNumber )
end
end
return string.format( "&%s;", aValue )
end
aString = string.gsub( aString, "&(%w+);", aFunction )
aString = string.gsub( aString, "&", "&" )
end
return aString
end
Alternatively, somebody, somewhere, somehow must have written this a
dozen time already. Is there not a little code sample somewhere to show
how to decode an XML string in Lua? Sigh...
Cheers
--
PA, Onnay Equitursay
http://alt.textdrive.com/