Re: access to lua arrays from within C code
[
Date Prev][
Date Next][
Thread Prev][
Thread Next]
[
Date Index]
[
Thread Index]
- Subject: Re: access to lua arrays from within C code
- From: Norman Ramsey <nr@...>
- Date: 1997年12月02日 08:10:50 -0500
> >I have a C function that expects char *argv[] as an argument.
> >The natural representation for argv in Lua would be as a table
> >with elements 1, 2, 3, etc.
> >
> >What is the recommended method of getting access to the array elements
> >from within my C code?
> for (i=0; i<N; i++)
> {
> lua_Object v;
> v=lua_param(i)
> if (v==LUA_NOOBJECT || lua_isnil(v)) break;
> argv[i]=lua_getnumber(v);
> }
I must not have stated my question very carefully.
I have something like this for treating a table as an array:
<<print the elements in [[list]] as indexed by small integers>>=
for (i = 1; ; i++) {
lua_Object o;
lua_pushobject(list);
lua_pushnumber((double)i);
o = lua_getsubscript();
if (lua_isnil(o)) break;
s = lua_getstring(o);
if (!s) lua_error("argument is not a string");
printf(" %s\n", s);
}
but there is no guarantee that a table I am passed actually represents
an array. I can't see how to find the number of non-nil entries in a
table, which is also awkward if I want to use tables to represent
sequences----it becomes difficult to write put, get, or append.
Norman