If you don't already know, these two models are the most common ways to store a tree in a relational DB.
Adjacency Model:
+-------------+----------------------+--------+
| category_id | name | parent |
+-------------+----------------------+--------+
| 1 | ELECTRONICS | NULL |
| 2 | TELEVISIONS | 1 |
| 3 | TUBE | 2 |
| 4 | LCD | 2 |
| 5 | PLASMA | 2 |
| 6 | PORTABLE ELECTRONICS | 1 |
| 7 | MP3 PLAYERS | 6 |
| 8 | FLASH | 7 |
| 9 | CD PLAYERS | 6 |
| 10 | 2 WAY RADIOS | 6 |
+-------------+----------------------+--------+
Nested Sets:
+-------------+----------------------+-----+-----+
| category_id | name | lft | rgt |
+-------------+----------------------+-----+-----+
| 1 | ELECTRONICS | 1 | 20 |
| 2 | TELEVISIONS | 2 | 9 |
| 3 | TUBE | 3 | 4 |
| 4 | LCD | 5 | 6 |
| 5 | PLASMA | 7 | 8 |
| 6 | PORTABLE ELECTRONICS | 10 | 19 |
| 7 | MP3 PLAYERS | 11 | 14 |
| 8 | FLASH | 12 | 13 |
| 9 | CD PLAYERS | 15 | 16 |
| 10 | 2 WAY RADIOS | 17 | 18 |
+-------------+----------------------+-----+-----+
You can also take a look here
I have a Table in adjacency Model in MySQL and I have decided to convert it to the nested sets model. I need a code to fill the LEFT
and RIGHT
columns based on the parent
column to mix them both and reach to something like this
What I need:
+-------------+----------------------+--------+-----+-----+
| category_id | name | parent | lft | rgt |
+-------------+----------------------+--------+-----+-----+
| 1 | ELECTRONICS | NULL | 1 | 20 |
| 2 | TELEVISIONS | 1 | 2 | 9 |
| 3 | TUBE | 2 | 3 | 4 |
| 4 | LCD | 2 | 5 | 6 |
| 5 | PLASMA | 2 | 7 | 8 |
| 6 | PORTABLE ELECTRONICS | 1 | 10 | 19 |
| 7 | MP3 PLAYERS | 6 | 11 | 14 |
| 8 | FLASH | 7 | 12 | 13 |
| 9 | CD PLAYERS | 6 | 15 | 16 |
| 10 | 2 WAY RADIOS | 6 | 17 | 18 |
+-------------+----------------------+--------+-----+-----+
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1You might want to check this one stackoverflow.com/questions/3623645/…Ammy T– Ammy T01/19/2015 12:09:27Commented Jan 19, 2015 at 12:09
-
Note: Nested sets are sometimes called Modified Pre-order Tree Traversal (MPTT), although I do much prefer nested sets :)icc97– icc9701/22/2024 16:03:05Commented Jan 22, 2024 at 16:03
1 Answer 1
Finally I found the solution but it needed some optimization and tweaks to work with my case and I added sorting with ID to get the tree sorted too, the answer is mainly got from here so credit goes to @deceze,
CREATE DEFINER=`root`@`localhost` PROCEDURE `tree_recover`()
MODIFIES SQL DATA
BEGIN
DECLARE currentId, currentParentId CHAR(36);
DECLARE currentLeft INT;
DECLARE startId INT DEFAULT 1;
# Determines the max size for MEMORY tables.
SET max_heap_table_size = 1024 * 1024 * 512;
START TRANSACTION;
# Temporary MEMORY table to do all the heavy lifting in,
# otherwise performance is simply abysmal.
DROP TABLE IF EXISTS `tmp_tree`;
CREATE TABLE `tmp_tree` (
`id` bigint(36) NOT NULL DEFAULT '0',
`parent` char(36) DEFAULT NULL,
`lft` int(11) unsigned DEFAULT NULL,
`rgt` int(11) unsigned DEFAULT NULL,
PRIMARY KEY (`id`),
INDEX USING HASH (`parent`),
INDEX USING HASH (`lft`),
INDEX USING HASH (`rgt`)
) ENGINE = MEMORY
SELECT `id`,
`parent`,
`lft`,
`rgt`
FROM `tree`;
# Leveling the playing field.
UPDATE `tmp_tree`
SET `lft` = NULL,
`rgt` = NULL;
# Establishing starting numbers for all root elements.
WHILE EXISTS (SELECT * FROM `tmp_tree` WHERE `parent` = 0 AND `lft` IS NULL AND `rgt` IS NULL LIMIT 1) DO
UPDATE `tmp_tree`
SET `lft` = startId,
`rgt` = startId + 1
WHERE `parent` = 0
AND `lft` IS NULL
AND `rgt` IS NULL
ORDER BY `id` ASC
LIMIT 1;
SET startId = startId + 2;
END WHILE;
# Switching the indexes for the lft/rgt columns to B-Trees to speed up the next section, which uses range queries.
DROP INDEX `lft` ON `tmp_tree`;
DROP INDEX `rgt` ON `tmp_tree`;
CREATE INDEX `lft` USING BTREE ON `tmp_tree` (`lft`);
CREATE INDEX `rgt` USING BTREE ON `tmp_tree` (`rgt`);
# Numbering all child elements
WHILE EXISTS (SELECT * FROM `tmp_tree` WHERE `lft` IS NULL LIMIT 1) DO
# Picking an unprocessed element which has a processed parent.
SELECT `tmp_tree`.`id`
INTO currentId
FROM `tmp_tree`
INNER JOIN `tmp_tree` AS `parents`
ON `tmp_tree`.`parent` = `parents`.`id`
WHERE `tmp_tree`.`lft` IS NULL
AND `parents`.`lft` IS NOT NULL
ORDER BY `tmp_tree`.`id` DESC
LIMIT 1;
# Finding the element's parent.
SELECT `parent`
INTO currentParentId
FROM `tmp_tree`
WHERE `id` = currentId;
# Finding the parent's lft value.
SELECT `lft`
INTO currentLeft
FROM `tmp_tree`
WHERE `id` = currentParentId;
# Shifting all elements to the right of the current element 2 to the right.
UPDATE `tmp_tree`
SET `rgt` = `rgt` + 2
WHERE `rgt` > currentLeft;
UPDATE `tmp_tree`
SET `lft` = `lft` + 2
WHERE `lft` > currentLeft;
# Setting lft and rgt values for current element.
UPDATE `tmp_tree`
SET `lft` = currentLeft + 1,
`rgt` = currentLeft + 2
WHERE `id` = currentId;
END WHILE;
# Writing calculated values back to physical table.
UPDATE `tree`, `tmp_tree`
SET `tree`.`lft` = `tmp_tree`.`lft`,
`tree`.`rgt` = `tmp_tree`.`rgt`
WHERE `tree`.`id` = `tmp_tree`.`id`;
COMMIT;
DROP TABLE `tmp_tree`;
END
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note that I'm also using
0
instead ofnull
for parent nodes!azerafati– azerafati01/20/2015 15:27:04Commented Jan 20, 2015 at 15:27